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Maslowich
3 years ago
11

When designing an experiment, why is it important to test only one variable?

Physics
2 answers:
m_a_m_a [10]3 years ago
6 0
That's the only way you can get consistent and accurate results. 
zheka24 [161]3 years ago
6 0
I will try to explain more in depth. Lets say Jimmy frequently has headaches and needs medicine to treat it. Jimmy uses Headfix and Achefix both in one experiment. The next day, Jimmy feels great. His headaches are cured, but since Jimmy used 2 variables (the 2 medicines), he is left with three options

a. Headfix worked
b. Achefix worked
c. Both worked.

Now Jimmy has no idea what solved his problem. It could be 3 possible answers. However, if he used one variable at a time and had two experiments instead, lets see what happens.

Jimmy uses Headfix.
a. It worked
b. It didn't work

Headfix did not work.

Next experiment Jimmy uses Achefix
a. It worked
b. It didn't work

Achefix worked.

Now instead of having three possible solutions, you have 1 definite answer experiment. Therefore you cannot use more than one variable because there could be multiple outcomes and you do not know which variable affected the results differently/
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It is easier to roll a stone up a sloping road than to lift it vertical upwards because.
kvasek [131]

Answer:

Because the force one needs to apply is reduced.

Explanation:

  • Work can be expressed in terms of force and distance as follows,

                        Work = Force × distance

  • To be more precise, the selection of these two parameters should be in a manner that the distance is what the line of action of the force traces.
  • It is obvious that for a given amount of work when one parameter is changed the other changes to counteract the change of the first one.
  • Imagine the situation shown in the attached figure. The amount of work that needs to be done during the lifting of the mass to a height of \small h vertically is E = mg\times h = mgh.
  • On the slope, however, one needs to push the object an L distance up to get the object to that h height ultimately.
  • The work he does on the slope is mgh = F\times L and sinceL > h , F < mg.
  • The force that needs to be applied is less than that applied in the vertical lift. Hence it feels easier.             #SPJ4                                                                    

3 0
1 year ago
Explain why wedges and screws are actually types of inclined planes.
slava [35]
<span>The screw is really just an inclined plane covered around with a tiny pole. The wedge is definitely an inclined plane, since it starts with a point, then rises getting thicker, as an inclined plane. </span>
5 0
3 years ago
Read 2 more answers
A student wants to get real and inverted
sveta [45]

Answer:

concave mirror

Explanation:

5 0
3 years ago
A charge of 4.5 × 10-5 C is placed in an electric field with a strength of 2.0 × 104 . If the charge is 0.030 m from the source
snow_tiger [21]

Answer:

The electrical potential energy is 0.027 Joules.

Explanation:

The values from the question are

charge (q) = 4.5 \times 10^{-5} C

Electric Field strength (E) = 2.0 \times 10^{4} N/C

Distance from source (d) = 0.030 m

Now the formula for the electrical potential energy (U) is given by

U = q \times E \times d

So now insert the values to find the answer

U = 4.5 \times 10^{-5} C \times 2.0 \times 10^{4} N/C \times 0.030 m

On further solving

U = 0.027 J

8 0
3 years ago
The center of the Hubble space telescope is 6940 km from Earth’s center. If the gravitational force between Earth and the telesc
Law Incorporation [45]
The gravitational force between two objects is given by:
F=G \frac{m_1 m_2}{r^2}
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is the separation between the two objects

The distance of the telescope from the Earth's center is r=6940 km=6.94 \cdot 10^6 m, the gravitational force is F=9.21 \cdot 10^4 N and the mass of the Earth is m_1=5.98 \cdot 10^{24} kg, therefore we can rearrange the previous equation to find m2, the mass of the telescope:
m_2 =  \frac{Fr^2}{Gm_1}= \frac{(9.21 \cdot 10^4 N)(6.94\cdot 10^6)^2}{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})} =11121 kg
6 0
3 years ago
Read 2 more answers
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