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3 years ago

When designing an experiment, why is it important to test only one variable?

Physics

2 answers:

m_a_m_a [10]3 years ago

6 0

That's the only way you can get consistent and accurate results.

zheka24 [161]3 years ago

6 0

I will try to explain more in depth. Lets say Jimmy frequently has headaches and needs medicine to treat it. Jimmy uses Headfix and Achefix both in one experiment. The next day, Jimmy feels great. His headaches are cured, but since Jimmy used 2 variables (the 2 medicines), he is left with three options

a. Headfix worked
b. Achefix worked
c. Both worked.

Now Jimmy has no idea what solved his problem. It could be 3 possible answers. However, if he used one variable at a time and had two experiments instead, lets see what happens.

Jimmy uses Headfix.
a. It worked
b. It didn't work

Headfix did not work.

Next experiment Jimmy uses Achefix
a. It worked
b. It didn't work

Achefix worked.

Now instead of having three possible solutions, you have 1 definite answer experiment. Therefore you cannot use more than one variable because there could be multiple outcomes and you do not know which variable affected the results differently/

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3 years ago

Explain how the meanings of the terms biotic factor and abiotic factor differ ?

Stells [14]

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3 years ago

Jeff puts on a leather jacket over his sweater. The sweater becomes negatively charged. Which statements about Jeff’s situation

nikdorinn [45]

b. The sweater has a tendency to attract protons.

8 0

3 years ago

Read 2 more answers

a train is moving with an initial velocity of 30 m/s, the brakes are applied so as to produce a uniform acceleration of -1.5 m/s

Pepsi [2]

Answer:

$\boxed{\sf Time \ in \ which \ train \ will \ come \ to \ rest = 20 \ sec}$

Given:

Initial velocity (u) = 30 m/s

Final speed (v) = 0 m/s

Acceleration (a) = - 1.5 m/,s²

To Find:

Time in which train will come to rest (t).

Explanation:

$\sf From \ equation \ of \ motion: \\ \sf \implies \bold{v = u + at} \\ \\ \sf Substituting \ value \ of \ v, \ u \ and \ a: \\ \sf \implies 0 = 30 + ( - 1.5)(t) \\ \sf \implies 0 = 30 - 1.5(t) \\ \sf \implies 30 - 1.5(t) = 0 \\ \\ \sf Subtract \: 30 \: from \: both \: sides: \\ \sf \implies (30 - \boxed{ \sf 30}) - 1.5(t) = \boxed{ \sf - 30} \\ \\ \sf 30 - 30 = 0 : \\ \sf \implies - 1.5(t) = - 30 \\ \\ \sf Divide \: both \: sides \: of \: - 1.5(t) = - 30 \: by \: - 1.5 : \\ \sf \implies \frac{ - 1.5(t)}{ \boxed{ \sf - 1.5}} = \frac{ - 30}{ \boxed{ \sf -1.5 }} \\ \\ \sf \frac{ \cancel{ \sf 1.5}}{\cancel{ \sf 1.5}} = 1 : \\ \sf \implies t = \frac{ - 30}{ - 1.5} \\ \\ \sf \frac{ - 30}{ - 1.5} = \frac{\cancel{ \sf 1.5} \times 20}{\cancel{ \sf 1.5}} = 20 : \\ \sf \implies t = 20 \: sec$

So,

Time in which train will come to rest = 20 seconds

4 0

2 years ago