Answer:
The concentration of the Cu²⁺ solution in the 10,0 mL volumetric flask is 5,425×10⁻³ M Cu²⁺
Explanation:
The first dilution from a 2,17M Cu²⁺ solution gives:
2,17 M Cu²⁺ ×
= <em>0,0217 M Cu²⁺solution</em>
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The second dilution gives as concentration:
0,0217 M Cu²⁺ ×
= 5,425×10⁻³ M Cu²⁺ solution
I hope it helps!
Answer:
2.0 M
Explanation:
Step 1: Given data
- Mass of NaCl (solute): 2.93 g
- Volume of the solution: 0.025 L
Step 2: Calculate the moles corresponding to 2.93 g of NaCl
The molar mass of NaCl is 58.44 g/mol.
2.93 g × 1 mol/58.44 g = 0.0501 mol
Step 3: Calculate the molarity of the solution
Molarity is equal to the moles of solute divided by the liters of solution.
M = 0.0501 mol/0.025 L = 2.0 M
