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4 years ago

Which of the following molecules can form hydrogen bonds? Group of answer choices NH3 NaH HI BH3 CH4

Chemistry

1 answer:

Len [333]4 years ago

8 0

Answer:

NH₃

Explanation:

The hydrogen bond is a specially strong type of dipole-dipole interaction. For a hydrogen bond to occur, a molecule must have a hydrogen atom and a very electronegative atom, such as nitrogen, oxygen or fluorine. The hydrogen atom has a positive charge density while the heteroatom has a negative charge density.

<em>Which of the following molecules can form hydrogen bonds? </em>

NH₃ YES

NaH NO

HI NO

BH₃ NO

CH₄ NO

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A 1.00 L volume of HCl reacted completely with 2.00 L of 1.50 M Ca(OH)2 according to the balanced chemical equation below. 2HCl

wolverine [178]

Answer:

$\boxed{\text{6.00 mol/L}}$

Explanation:

(a) Balanced equation

2HCl + Ca(OH)₂ ⟶ CaCl₂ + 2H₂O

(b) Moles of Ca(OH)₂

$\text{Moles of base} = \text{2.00L} \times \dfrac{\text{1.50 mol}}{\text{1 L}} = \text{3.000 mol base}$

(c) Moles of HCl

$\text{Moles of HCl} = \text{3.000 mol base} \times \dfrac{ \text{2 mol HCl}}{\text{1 mol base}} = \text{6.000 mol HCl}$

(d) Molar concentration of HCl

$\text{Molar concentration} = \dfrac{\text{moles of solute}}{\text{litres of solution}}\\\\c = \dfrac{ n }{ V}\\\\c= \dfrac{ \text{6.000 mol}}{ \text{1.000 L}} = \text{6.00 mol/L}$

The molar concentration of the HCl was $\boxed{\textbf{6.00 mol/L}}$

6 0

3 years ago

Read 2 more answers

How do ionic compounds and molecular compounds behave<br> differently in solution?

Lelu [443]

Answer : Molecular compounds dissolve in water by means of dipole-dipole attractions and hydrogen bond attractions. These attractions between the molecular compound and water don't form ions when a molecular compound dissolves.

Explanation: I hoped that helped,

6 0

3 years ago

A hot-air balloon is filled with air to a volume of 3000 m3 at 750 torr and 21°C. The air in the balloon is then heated to 60.°C

valina [46]

Answer: 1.47

Explanation:

The combined gas equation when pressure is constant:

$\frac{V_1}{n_1T_1}=\frac{V_2}{n_2T_2}$

where,

$n_1$ =original number of moles of air in the balloon = ?

$n_2$ = number of moles of air in the heated balloon = ?

$V_1$ = initial volume of gas = $3000m^3$

$V_2$ = final volume of gas = $5000m^3$

$T_1$ = initial temperature of gas = $21^oC=273+21=294K$

$T_2$ = final temperature of gas = $60^oC=273+60=333K$

Now put all the given values in the above equation, we get the final pressure of gas.

$\frac{3000}{n_1\times 294K}=\frac{5000}{n_2\times 333K}$

$\frac{n_2}{n_1}=1.47$

Therefore, the ratio of the number of moles of air in the heated balloon to the original number of moles of air in the balloon is 1.47

5 0

3 years ago

The chemist discovers a more efficient catalyst that can produce ethyl butyrate with a 78.0% yield. How many grams would be prod

Vedmedyk [2.9K]

The grams that would be produced from 7.70 g of butanoic acid and excess ethanol is 7.923grams

calculation

Step 1: write the chemical equation for the reaction

CH3CH2CH2COOH + CH3CH2OH → CH3CH2CH2COOCH2CH3 +H2O

step 2: find the moles of butanoic acid

moles= mass/ molar mass

= 7.70 g/ 88 g/mol=0.0875 moles

Step 3: use the mole ratio to determine the moles of ethyl butyrate

moles ratio of CH3CH2CH2COOH :CH3CH2CH2COOCH2CH3 is 1:1 therefore the moles of CH3CH2CH2COOCH2CH3 = 0.0875 x78/100=0.0683moles

step 4: find mass = moles x molar mass

= 0.0683 moles x116 g/mol=7.923grams

5 0

3 years ago

Read 2 more answers

Which law represents a balanced chemical equation?

Montano1993 [528]

Answer:

All chemical equations goes to the law of conservation of mass which says that matter can not be destroyed nor created which means there has to be an equal amount of atoms of each element on both sides of the equation. I hope that helps, I'm learning this as well.

8 0

3 years ago