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irina1246 [14]
3 years ago
6

A fast-moving vw beetle traveling at 54 mph hit a mosquito hovering at rest above the road. which bug experienced the largest fo

rce? 1. the insect 2. the vw 3. unable to determine 4. they experienced the same magnitude of force
Physics
2 answers:
Ad libitum [116K]3 years ago
8 0

Answer: 4 they both experienced same magnitude of force.

Explanation:

According to Newton's 3rd law of motion,it implies that for every force exerted by an object on another object is the same magnitude directed back.

The force the VW beetle has when it hits the mosquito was the same force exerted on the mosquito on impact.

Therefore the magnitude of their forces are the same.

allsm [11]3 years ago
3 0
1. the insect
because of how fast the car is going and how small they are
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What is a methane. please answer pysicsssssssssss​
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Answer:

Methane is a colorless, odorless flammable gas which is the main constituent of natural gas. It is the simplest member of the alkane series of hydrocarbons.

Explanation:

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4 years ago
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A water-skier is moving at a speed of 14.3 m/s. When she skis in the same direction as a traveling wave, she springs upward ever
kiruha [24]

Answer:

a) 1.95 m/s

b) 5.56 m

Explanation:

Given that:

Velocity of the skier (V_s) = 14.3 m/s

For the skier moving in the direction of the wave, we have:

Period (T) = 0.450 s

Relative velocity (V) of the skier in regard with the wave =  (V_s - V_w)

where:

V_s = velocity of the skier

V_w = velocity of the wave

The wavelength (\lambda) can be written as:

\lambda = (V_s-V_w)T

\lambda = (V_s-V_w) 0.450m ---------------> Equation (1)

For the skier moving opposite in the direction of the wave, we have:

Period (T) = 0.342 s

Relative velocity (V) of the skier in regard with the wave = (V_s + V_w)

The wavelength (\lambda) can be written as:

\lambda = (V_s+V_w)T

\lambda = (V_s+V_w) 0.342m   ------------------> Equation 2

Equating equation (1) and equation (2) and substituting  V_s  = 14.3 m/s ; we have:

(V_s-V_w) 0.450m  =  (V_s-V_w) 0.342m

0.450m(V_s)-0.450m(V_w)   =  0.342m(V_s)+0.342m(V_w)

Collecting the like terms; we have:

0.450m(V_s) - 0.342m(V_s) =  0.342m(V_w)+0.450m(V_w)

(V_s)(0.450m - 0.342m) =  (V_w)0.342m+0.450m

14.3m/s(0.450m - 0.342m) =  (V_w)0.342m+0.450m

14.3m/s(0.108m =  (V_w)0.792m

1.5444m^2/s =  (V_w)0.792m

(V_w) = \frac{1.5444m^2/s}{ 0.792m}

(V_w) = 1.95 m/s

b)

The Wavelength of the wave can be calculated using :  ( \lambda }) = (V_s-V_w) 0.450m

({\lambda}) = (14.3 m/s -1.95 m/s)(0.450)

(\lambda) = (12.35)0.450m

(\lambda)= 5.5575 m

λ ≅ 5.56 m

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3 years ago
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Answer:

Mb²/2

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Pls see attached file

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its true i thank

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Function . . . the pipe that carries food down from your mouth to your stomach.

Location . . . straight down your throat inside your neck.
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