To pass signals around the bod from the brain
The equivalent resistance is D) ![7.55 \Omega](https://tex.z-dn.net/?f=7.55%20%5COmega)
Explanation:
The equivalent resistance of n resistors in parallel is given by the equation:
![\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+...+\frac{1}{R_n}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BR%7D%3D%5Cfrac%7B1%7D%7BR_1%7D%2B%5Cfrac%7B1%7D%7BR_2%7D%2B...%2B%5Cfrac%7B1%7D%7BR_n%7D)
For three resistors such as in this problem, the equation becomes
![\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BR%7D%3D%5Cfrac%7B1%7D%7BR_1%7D%2B%5Cfrac%7B1%7D%7BR_2%7D%2B%5Cfrac%7B1%7D%7BR_3%7D)
where we have the following:
is the resistance of the 1st resistor
is the resistance of the 2nd resistor
is the resistance of the 3rd resistor
Substituting, we find the equivalent resistance:
![\frac{1}{R}=\frac{1}{10}+\frac{1}{50}+\frac{1}{80}=0.133 \Omega^{-1}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BR%7D%3D%5Cfrac%7B1%7D%7B10%7D%2B%5Cfrac%7B1%7D%7B50%7D%2B%5Cfrac%7B1%7D%7B80%7D%3D0.133%20%5COmega%5E%7B-1%7D)
![R=\frac{1}{0.133}=7.55 \Omega](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B1%7D%7B0.133%7D%3D7.55%20%5COmega)
Learn more about resistance:
brainly.com/question/2364338
brainly.com/question/12246020
#LearnwithBrainly
The hottest layer in Sun's atmosphere is the Corona.
The sun's atmosphere is composed of three main layers.
1. Photosphere- the lowest layer and closest in distance from the the sun's core. It has an average temperature of 5,800 degrees Kelvin. It usually appears granulated and bubbly, like a simmering pot of water.
2.Chromosphere- extends above the photosphere to about 2000 km. Its temperature is 4,500 - 10,000 degrees Kelvin.
3. Corona - outermost layer of the sun, extending several million kilometers outward from the chromosphere into space. The average temperature averages 2 million degrees Kelvin. It is thought the sun's magnetism is the reason that the corona is so hot.
Complete Question
A toroidal solenoid has 590 turns, cross-sectional area 6.20 cm^2 , and mean radius 5.00 cm .
Part A. Calculate the coil's self-inductance.
Part B. If the current decreases uniformly from 5.00 A to 2.00 A in 3.00 ms, calculate the self-induced emf in the coil.
Part C. The current is directed from terminal a of the coil to terminal b. Is the direction of the induced emf from a to b or from b to a?
Answer:
Part A
![L = 0.000863 \ H](https://tex.z-dn.net/?f=L%20%20%3D%200.000863%20%5C%20H)
Part B
![\epsilon = 0.863 \ V](https://tex.z-dn.net/?f=%5Cepsilon%20%20%3D%20%200.863%20%5C%20V)
Part C
From terminal a to terminal b
Explanation:
From the question we are told that
The number of turns is ![N = 590 \ turns](https://tex.z-dn.net/?f=N%20%20%3D%20%20590%20%5C%20turns)
The cross-sectional area is ![A = 6.20 cm^2 = 6.20 *10^{-4} \ m](https://tex.z-dn.net/?f=A%20%20%3D%20%206.20%20cm%5E2%20%3D%20%206.20%20%2A10%5E%7B-4%7D%20%5C%20%20m)
The radius is ![r = 5.0 \ cm = 0.05 \ m](https://tex.z-dn.net/?f=r%20%3D%20%205.0%20%5C%20cm%20%20%3D%200.05%20%5C%20m)
Generally the coils self -inductance is mathematically represented as
![L = \frac{ \mu_o N^2 A }{2 \pi * r }](https://tex.z-dn.net/?f=L%20%20%3D%20%5Cfrac%7B%20%5Cmu_o%20%20N%5E2%20%20A%20%7D%7B2%20%5Cpi%20%20%2A%20%20r%20%7D)
Where
is the permeability of free space with value ![\mu_o = 4\pi * 10^{-7} N/A^2](https://tex.z-dn.net/?f=%5Cmu_o%20%20%3D%20%204%5Cpi%20%2A%2010%5E%7B-7%7D%20N%2FA%5E2)
substituting values
![L = \frac{ 4\pi * 10^{-7} * 590^2 6.20 *10^{-4} }{2 \pi * 0.05 }](https://tex.z-dn.net/?f=L%20%20%3D%20%5Cfrac%7B%204%5Cpi%20%2A%2010%5E%7B-7%7D%20%2A%20%20590%5E2%20%206.20%20%2A10%5E%7B-4%7D%20%7D%7B2%20%5Cpi%20%20%2A%20%200.05%20%7D)
![L = \frac{ 2 * 10^{-7} * 590^2 6.20 *10^{-4} }{ 0.05 }](https://tex.z-dn.net/?f=L%20%20%3D%20%5Cfrac%7B%202%20%2A%2010%5E%7B-7%7D%20%2A%20%20590%5E2%20%206.20%20%2A10%5E%7B-4%7D%20%7D%7B%20%20%20%200.05%20%7D)
![L = 0.000863 \ H](https://tex.z-dn.net/?f=L%20%20%3D%200.000863%20%5C%20H)
Considering the Part B
Initial current is ![I_1 = 5.00 \ A](https://tex.z-dn.net/?f=I_1%20%3D%20%205.00%20%5C%20A)
Current at time t is ![I_t = 3.0 \ A](https://tex.z-dn.net/?f=I_t%20%3D%20%203.0%20%5C%20A)
The time taken is ![\Delta t = 3.00 ms = 0.003 \ s](https://tex.z-dn.net/?f=%5CDelta%20t%20%3D%20%203.00%20ms%20%3D%20%200.003%20%5C%20s)
The self-induced emf is mathematically evaluated as
=> ![\epsilon = L * \frac{ I_1 - I_t }{ \Delta t }](https://tex.z-dn.net/?f=%5Cepsilon%20%20%3D%20%20L%20%20%2A%20%20%5Cfrac%7B%20I_1%20-%20%20I_t%20%7D%7B%20%5CDelta%20t%20%7D)
substituting values
![\epsilon = 0.863 \ V](https://tex.z-dn.net/?f=%5Cepsilon%20%20%3D%20%200.863%20%5C%20V)
The direction of the induced emf is from a to b because according to Lenz's law the induced emf moves in the same direction as the current
Answer:
trade and agriculture
Explanation:
i got it right on the test