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ch4aika [34]
3 years ago
7

A 45-mH inductor is connected in series with a 60-Ω resistor through a 15-V dc power supply and a switch. If the switch is close

d at t = 0 s, what is the current after 7.0 ms?
Physics
1 answer:
egoroff_w [7]3 years ago
4 0

Answer:

The current is 0.248 A

Explanation:

Given that,

Inductor L= 45\times10^{3}\ H

Resistance R= 60\Omega

Voltage = 15 volt

Time t =7.0\times10^{-3}\ sec

We need to calculate the current

Using formula of current

I=\dfrac{V}{R}(1-e^{\dfrac{-R}{L}}t)

Where, V = voltage

R = resistance

L = inductance

T = time

Put the value into the formula

I=\dfrac{15}{60}(1-e^{\dfrac{-60}{45\times10^{3}}}\times7\times10^{-3})

I=0.248\ A

Hence, The current is 0.248 A.

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