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otez555 [7]
3 years ago
13

The density of the liquid flowing through a horizontal pipe is 1200 kg/m3. The speed of the fluid at point A is 7.5 m/s while at

point B it is 11 m/s. What is the difference in pressure, PB – PA, between points B and A?A. +5.0 × 104 PaB. –1.9 × 103 PaC. –2.5 × 104 PaD. –3.9 × 104 PaE. +3.8 × 103 Pa
Physics
1 answer:
Rufina [12.5K]3 years ago
8 0

Answer:

The difference in pressure between points B and A is -3.9\times10^{4}\ Pa

(D) is correct option.

Explanation:

Given that,

Density of the liquid = 1200 kg/m³

Speed of fluid at point A= 7.5 m/s

Speed of fluid at point B = 11 m/s

We need to calculate the difference in pressure between points B and A

Using formula of change in pressure

\Delta P=\dfrac{1}{2}D(v_{2}^2-v_{1}^2)

Where, v_{1} = Speed of fluid at point A

v_{2} = Speed of fluid at point B

D = Density of the liquid

Put the value into the formula

\Delta P=\dfrac{1}{2}\times1200\times(11^2-7.5^2)

\Delta P=-38850\ Pa

\Delta P=-3.9\times10^{4}\ Pa

Hence, The difference in pressure between points B and A is -3.9\times10^{4}\ Pa

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Since we only have 2 sig figs, and since 1kJ =- 1000J

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1 year ago
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swat32

Answer:

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b) The drift velocity Vd= 1.51×10^-15

Explanation:

The equation for the current density and drift velocity is given by:

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