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3 years ago

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The density of the liquid flowing through a horizontal pipe is 1200 kg/m3. The speed of the fluid at point A is 7.5 m/s while at

point B it is 11 m/s. What is the difference in pressure, PB – PA, between points B and A?A. +5.0 × 104 PaB. –1.9 × 103 PaC. –2.5 × 104 PaD. –3.9 × 104 PaE. +3.8 × 103 Pa

1 answer:

Rufina [12.5K]3 years ago

8 0

Answer:

The difference in pressure between points B and A is $-3.9\times10^{4}\ Pa$

(D) is correct option.

Explanation:

Given that,

Density of the liquid = 1200 kg/m³

Speed of fluid at point A= 7.5 m/s

Speed of fluid at point B = 11 m/s

We need to calculate the difference in pressure between points B and A

Using formula of change in pressure

$\Delta P=\dfrac{1}{2}D(v_{2}^2-v_{1}^2)$

Where, $v_{1}$ = Speed of fluid at point A

$v_{2}$ = Speed of fluid at point B

D = Density of the liquid

Put the value into the formula

$\Delta P=\dfrac{1}{2}\times1200\times(11^2-7.5^2)$

$\Delta P=-38850\ Pa$

$\Delta P=-3.9\times10^{4}\ Pa$

Hence, The difference in pressure between points B and A is $-3.9\times10^{4}\ Pa$

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