Use the pie section above to answer this question.

MaRussiya [10]

No, it does not. I believe it's false.

6 0

2 years ago

Suppose 12.0 g of carbon (c) reacts with 70.0 g of sulfur (s) to give 76.0 g of the compound carbon disulfide 1 c s 2 2 . In the

Nitella [24]

Answer is: mass of unused sulfur is 5.87 grams.

Balanced chemical reaction: C + 2S → CS₂.

m(C) = 12.0 g; mass of carbon.

m(S) = 70.0 g; mass of sulfur.

n(C) = m(C) ÷ M(C).

n(C) = 12 g ÷ 12 g/mol.

n(C) = 1 mol; amount of substance.

n(S) = m(S) ÷ M(S).

n(S) = 70 g ÷ 32.065 g/mol.

n(S) = 2.183 mol.

From chemical reaction: n(C) : n₁(S) = 1 : 2.

n₁(S) = 1 mol · 2 = 2 mol.

Δn(S) = n(S) - n₁(S).

Δn(S) = 2.183 mol - 2 mol.

Δn(S) = 0.183 mol; amount of unused sulfur.

Δm(S) = 0.183 mol · 32.065 g/mol.

Δm(S) = 5.87 g.

4 0

3 years ago

I need some help this is due soon

nikitadnepr [17]

Answer:

catalysts help speed up reactions which implies that they provide a alternative pathway and when there is less activation energy more particles have more energy to react

5 0

2 years ago

1Calculate the density of an object that has a mass of 84.7g and a volume of 59.3 cm3

Iteru [2.4K]

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 84.7 g

volume = 59.3 cm³

We have

$density = \frac{84.7}{59.3} \\ = 1.428330...$

We have the final answer as

Hope this helps you

7 0

3 years ago

A gas cylinder contains 2.0 mol of gas X and 6.0 mol of gas Y at a total pressure of 2.1 atm. What is the partial pressure of ga

vivado [14]

Answer : The partial pressure of X and Y gases are, 0.525 and 1.575 atm respectively.

Explanation : Given,

Moles of X = 2.0 mole

Moles of Y = 6.0 mole

Total pressure = 2.1 atm

Now we have to calculate the mole fraction of X and Y.

$\text{Mole fraction of }X=\frac{\text{Moles of }X}{\text{Moles of }X+\text{Moles of }Y}$

$\text{Mole fraction of }X=\frac{2.0}{2.0+6.0}=0.25$

and,

$\text{Mole fraction of }Y=\frac{\text{Moles of }Y}{\text{Moles of }X+\text{Moles of }Y}$

$\text{Mole fraction of }Y=\frac{6.0}{2.0+6.0}=0.75$

Now we have to calculate the partial pressure of X and Y.

According to the Raoult's law,

$p_i=X_i\times p_T$

where,

$p_i$ = partial pressure of gas

$p_T$ = total pressure of gas = 2.1 atm

$X_i$ = mole fraction of gas

$p_{X}=X_{(X)}\times p_T$

$p_{X}=0.25\times 2.1atm=0.525atm$

and,

$p_{Y}=X_{(Y)}\times p_T$

$p_{Y}=0.75\times 2.1atm=1.575atm$

Thus, the partial pressure of X and Y gases are, 0.525 and 1.575 atm respectively.

4 0

3 years ago

Read 2 more answers