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Doss [256]
3 years ago
8

If 2 electrically charged objects repel one another , which of the statements could be true, one object has more electrons, the

other has more protons, both objects have same electrical charge, the objects don't have strong electrical fields, electrons will flow from one object to the other when they touch.
Physics
2 answers:
Serggg [28]3 years ago
8 0

Answer:

have the same electron charge

Explanation:

fiasKO [112]3 years ago
6 0
Both objects have the same electrical charge. Opposite charges attract. And if they were neutral they would not do anything.
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None of the above.

The correct answer would be momentum

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Can someone help me?​
Leviafan [203]

Car X traveled 3d distance in t time.  Car Y traveled 2d distance in t time. Therefore, the speed of car X, is 3d/t,  the speed of car Y, is 2d/t. Since speed is the distance taken in a given time.

In figure-2, they are at the same place, we are asked to find car Y's position when car X is at line-A. We can calculate the time car X needs to travel to there. Let's say that car X reaches line-A in t' time.

V_x .t' = 3d\\ \frac{3d}{t} .t' = 3d\\ t'=t

Okay, it takes t time for car X to reach line-A. Let's see how far does car Y goes.

V_y.t = \frac{2d}{t} .t = 2d

We found that car Y travels 2d distance. So, when car X reaches line-A, car Y is just a d distance behind car X.

4 0
3 years ago
15. An e.mf. of 16 volts is induced in a coil of inductance 4H. The rate of change of current must be:
alex41 [277]
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7 0
3 years ago
1.
Gwar [14]

<u>Answer:</u>

For 1: The correct option is Option C.

For 3: The final velocity of the opponent is 1m/s

<u>Explanation: </u>

During collision, the energy and momentum remains conserved. The equation for the conservation of momentum follows:

m_1u_1+m_2u_2=m_1v_1+m_2v_2      ...(1)

where,

m_1,u_1\text{ and }v_1 are the mass, initial velocity and final velocity of first object

m_2,u_2\text{ and }v_2 are the mass, initial velocity and final velocity of second object

<u>For 1:</u>

We are Given:

m_1=150g=0.15kg\\u_1=?m/s\\v_1=0.85m/s\\m_2=3500g=3.5kg\\u_2=0m/s\\v_2=0.85m/s

Putting values in equation 1, we get:

(0.15\times u_1)+(3.5\times 0)=(3.5+0.15)\times 0.85\\\\u_1=20.683\approx 21m/s

Hence, the correct answer is Option C.

  • <u>For 2: </u>

Impulse is defined as the product of force applied on an object and time taken by the object.

Mathematically,

J=F\times t

where,

F = force applied on the object

t = time taken

J = impulse on that object

Impulse depends only on the force and time taken by the object and not dependent on the surface which is stopping the object.

Hence, the impulse remains the same.

  • <u>For 3:</u>

Let the speed in right direction be positive and left direction be negative.

We are Given:

m_1=240kg\\u_1=0m/s\\v_1=-1m/s\\m_2=80kg\\u_2=-2m/s\\v_2=?m/s

Putting values in equation 1, we get:

(240\times 0)+(80\times (-2))=(240\times (-1))+(80\times v_2)\\\\v_2=1m/s

Hence, the final velocity of the opponent is 1m/s and has moved backwards to its direction of the initial velocity.

4 0
3 years ago
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