Explanation:
The given data is as follows.
Heat transfer coefficient (h) = 12
Plate temperature (
) = 
= 303 K
Steady state temperature (
) = ?
Hence, formula applied for steady state is as follows.
= 
Putting the given values into the above formula as follows.
=
= ![5.67 \times 10^{-8} \times [(30 + 273)^{4} - T^{4}_{2}]](https://tex.z-dn.net/?f=5.67%20%5Ctimes%2010%5E%7B-8%7D%20%5Ctimes%20%5B%2830%20%2B%20273%29%5E%7B4%7D%20-%20T%5E%7B4%7D_%7B2%7D%5D)
= 282.66 K
= (282.66 -273)
= 9.66
Thus, we can conclude that the steady state temperature will be 9.66 .
The patient should be given 285.71 ml.
1000 ml contains 70 gr glucose.
x contains 20 gr glucose.
x=1000*20/70
Answer:
Adding a solution containing an anion that forms an insoluble salt with only one of the metal ions.
Explanation:
The student have in solution Ag⁺ and Cu²⁺ ions but he just want to analyze the silver, that means he need to separate ions.
Centrifuging the solution to isolate the heavier ions <em>FALSE </em>Centrifugation allows the separation of a suspension but Ag⁺ and Cu²⁺ are both soluble in water.
Adding enough base solution to bring the pH up to 7.0 <em>FALSE </em>At pH = 7,0 these ions are soluble in water and its separation will not be possible.
Adding a solution containing an anion that forms an insoluble salt with only one of the metal ions <em>TRUE </em>For example, the addition of Cl⁻ will precipitate the Ag⁺ as AgCl(s) allowing its separation.
Evaporating the solution to recover the dissolved nitrates. <em>FALSE</em> . Thus, you will obtain the nitrates of these ions but will be mixed doing impossible its separation.
I hope it helps!
Answer:
47.5 g of water can be formed
Explanation:
This is the reaction:
CH₄ + 2O₂ → CO₂ + 2H₂O
Methane combustion.
In this process 1 mol of methane react with 2 moles of oxygen to produce 2 moles of water and 1 mol of carbon dioxide.
As ratio is 1:2, I will produce the double of moles of water, with the moles of methane I have.
1.320 mol .2 = 2.64 moles
Now, we can convert the moles to mass (mol . molar mass)
2.64 mol . 18g/mol = 47.5 g
Boron:atomic number-5,valency-+3,atomic mass- 11amu
