N2+3H2= 2NH3
Stoichiometry: 1 mole of N2 + 3 moles of H2 yield 2 moles of ammonia, let's put that into grams; 28g (14g/mol∗2mol) of N2 and 6.06g(1.01g/mol∗2∗3mol)
yields 13.03g
We first have to find Q calorimeter
Q calorimeter = C (delta T)
C= heat capacity in J/oC, not small c ( specific heat capacity)
delta T= change in T (oC) = final T - initial T
Q calorimeter = 10.4 J/oC (30 oC - 25 oC)
Q calorimeter = 52 J
Remember,
Q calorimeter = - Q surrounding
The (-) negative sign stands for heat being released.
So ,
Q surrounding = - 52 J
In other words, the iron releases 52 J .
The calorimeter absorbs the entire 52 J and heat rose from 25 - 30 oC.
Answer: 52 J
Answer:
The specific heat of gold is 0.129 J/g°C
Explanation:
Step 1: Data given
Mass of gold = 15.3 grams
Heat absorbed = 87.2 J
Initial temperature = 35.0 °C
Final temperature = 79.2 °C
Step 2:
Q = m*c*ΔT
⇒ Q =the heat absorbed = 87.2 J
⇒ m = the mass of gold = 15.3 grams
⇒ c = the specific heat of gold = TO BE DETERMINED
⇒ ΔT = The change in temperature = T2 - T1 = 79.2 - 35.0 = 44.2 °C
87.2 J = 15.3g * c * 44.2°C
c = 87.2 / (15.3 * 44.2)
c = 0.129 J/g°C
The specific heat of gold is 0.129 J/g°C
Answer:
60 mph (miles per hour)
Explanation:
0.5 hours is 1/2 of an hour, so to get the number of miles for a whole hour you multiply the miles ran by 2.
30 times 2 is 60.
