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Damm [24]
4 years ago
6

There are 3.3V passing through an orange power supply cable, and there are 0.025 ohms of resistance in the orange wire. How much

power is supplied to the orange wire by the power supply?
Physics
1 answer:
PIT_PIT [208]4 years ago
5 0
P = V^2 / R.

So, 3.3^2 / 0.025 = 435.6W.

Note, you can get the power equation from:
P = V*I. Also, I = V/R.
Substituting V/R in for I in the 1st equation, you get P = V^2 / R.
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Sunny_sXe [5.5K]

That part of the wave is called a compression.

8 0
4 years ago
Read 2 more answers
The bogus pipeline is an instrument that was developed to measure attitudes that are otherwise difficult to measure because ____
VMariaS [17]

Answer:

of motivations to give a socially desirable response

Explanation:

The bogus pipeline is nothing but a polygraph machine which is fake.

With the help of a polygraph test it can be determined whether a person is telling the truth. This is done by measuring physiological indicators of a human being such as  blood pressure, respiration, pulse, and skin conductivity.

The bogus pipeline appears to be like a real polygraph machine. It is assumed that people will be truthful as they believe that the machine is real. Nowadays, it is used to measure attitude towards a certain stimulus.

6 0
3 years ago
A single sports fan is capable of yelling at an intensity level of 80 decibels from a given distance. If 10,000 similar fans wer
AleksandrR [38]

Answer:

The correct answer is part 'c' 160 dB

Explanation:

When noise levels of different intensities are superimposed the resultant intensity is given by the equation

L_{avg}=20log(\frac{1}{N}\sum_{i=1}^{N}(10^{\frac{L_{i}}{20}}))\\

where,

L_{i} is the intensity of a general sound level

Since we have 10000 fans each producing sound of 80dB thus the resultant intensity is given using the above formula as

L_{avg}=20log(\frac{1}{10000}\sum_{i=1}^{10000}(10^{\frac{80}{20}}))\\

\therefore L_{eq}=160dB

7 0
3 years ago
If you install special sound-reflecting windows that reduce the sound intensity level by 30.0 db , by what factor have you reduc
shusha [124]

Answer: The sound intensity was reduced by -14.77 dB.

Explanation:

The level of the intensity of the sound with respect to the reference value is called Sound Intensity level.

L_I=10\log\frac{I}{I_o} dB

I = Intensity of the sound

I_o = Reference sound intensity

According to question, sound-reflecting windows that reduce the sound intensity level by 30.0 db .

Let the intensity of the sound be I_o and reduced intensity be I.

I=\frac{I_o}{30} dB

L_I=10\log\frac{I}{I_o} dB

L_I=10\log\frac{\frac{I_o}{30}}{I_o}=10\log\frac{1}{30} dB=-14.77 dB

The sound intensity was reduced by -14.77 dB.

3 0
4 years ago
The distance between tow objects is increased by 3 times the original distance. How will this change the force of attraction bet
lys-0071 [83]

Answer:

force of attraction will be increased by 9

Explanation:

force of attraction is inversely proportional to square of distance

i.e F= 1/R²

F=1/3R²

F=1/9R

  • multiply both side by 9

9×F= 9×1/9R

9F= 1/R

so force of attraction is 9 times

8 0
3 years ago
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