You're going to use the constant acceleration motion equation for velocity and displacement:
(V)final² = (V)initial²+2a(dx)
Given:
a=0.500m/s²
dx=6.32 m
(V)intial=0m
(V)final= UNKNOWN
(V)final= 2.51396m/s
Answer:
somewhere between 32 m/s and 2 m/s
Explanation:
If the acceleration is applied in the same direction as the original motion, the motion increases.
17 + 3(5) = 32 m/s
If the acceleration is applied in the opposite direction as the original motion, the motion decreases.
17 - 3(5) = 2 m/s
If the acceleration is applied at an angle to the original motion, then we need to vector add original 17 m/s and the acceleration caused 15 m/s to find the final result. We would need the angle in ANY of these cases as velocity is a vector.
The final velocity of the red barge in the collision elastic is 0.311 m/s when it collides with blue barge pf mass 1000000 kg.
Final velocity(v3) of the red barge is calculated by following formula
m1×v1+ m2×v2= (m1+m2)v3
Substituting the value of m1= 150000 kg, v1= 0.25 m/s, m2= 1000000 kg, v2= 0.32 m/s
150000 × 0.25+ 1000000×0.32= (150000+1000000)×v3
37500+ 320000= 1150000×v3
357500= 1150000×v3
v3= 0.311 m/s
<h3>What is elastic collision velocity? </h3>
- The velocity of the target particle after a head-on elastic impact in which the projectile is significantly more massive than the target will be roughly double that of the projectile, but the projectile velocity will remain virtually unaltered.
For more information on elastic collision velocity kindly visit to
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2.440
X 107. The magnitude
------------ Is 261.080 plz
17.080. Make the
00.000. Brainliest
244.000
----------------
261.080
Answer:
Explanation:
Given
Speed of Primary wave
Speed of secondary wave
difference in timing of two waves are
Suppose both travel a distance of d km then
Subtract (ii) from (i)