Answer:
a) 0.022%
b) 10014.32 lb
Explanation:
a) Percentage uncertainty would be
Percent uncertainty is 0.022%
b) For 1 kg uncertainty mass in kg would be
Mass in pounds would be
Mass in pound-mass is 10014.32 lb
My response to question (a) and (b) is that all of the element of the rope need to aid or support the weight of the rope and as such, the tension will tend to increase along with height.
Note that It increases linearly, if the rope is one that do not stretch. So, the wave speed v= √ T/μ increases with height.
<h3>How does tension affect the speed of a wave in a rope?</h3>
The Increase of the tension placed on a string is one that tends to increases the speed of a wave, which in turn also increases the frequency of any given length.
Therefore, My response to question (a) and (b) is that all of the element of the rope need to aid or support the weight of the rope and as such, the tension will tend to increase along with height. Note that It increases linearly, if the rope is one that do not stretch. So, the wave speed v= √ T/μ increases with height.
Learn more about tension from
brainly.com/question/2008782
#SPJ4
See full question below
(a) If a long rope is hung from a ceiling and waves are sent up the rope from its lower end, why does the speed of the waves change as they ascend? (b) Does the speed of the ascending waves increase or decrease? Explain.
Answer:
Both
Explanation:
The lithosphere is part of both the crust and the mantle.
It is the surface layer of the earth and also the most rigid layer. It is formed by the crust and the outermost part of the mantle. It is divided into two types: continental lithosphere and oceanic lithosphere.
The oceanic lithosphere has an approximate thickness of 50 - 100km, and the continental olithosphere of 40 - 200km.
Answer:
The magnitude of the change in momentum of the stone is 5.51kg*m/s.
Explanation:
the final kinetic energy = 1/2(0.15)v^2
1/2(0.15)v^2 = 70%*1/2(0.15)(20)^2
v^2 = 21/0.075
v^2 = 280
v = 16.73 m.s
if u is the initial speed and v is the final speed, then:
u = 20 m/s and v = - 16.73m/s
change in momentum = m(v-u)
= 0.15(- 16.73-20)
= -5.51 kg*m.s
Therefore, The magnitude of the change in momentum of the stone is 5.51kg*m/s.
