If the toy car moved with a velocity of 2m/s to the south for 8s; what is the total displacement of the toy car?

Juan and Kuri are on a carousel. Juan is closer to the center of the carousel than Kuri. Which statement describes their tangent

Licemer1 [7]

Answer:

Juan and Kuri complete one revolution in the same time, but Juan travels a shorter distance and has a lower speed.

Explanation:

Since Juan is closer to the center and Kuri is away from the center so we can say that Juan will move smaller distance in one complete revolution

As we know that the distance moved in one revolution is given as

$d = 2\pi r$

also the time period of revolution for both will remain same as they move with the time period of carousel

Now we can say that the speed is given as

$v = \frac{2\pi r}{T}$

so Juan will have less tangential speed. so correct answer will be

Juan and Kuri complete one revolution in the same time, but Juan travels a shorter distance and has a lower speed.

6 0

3 years ago

Read 2 more answers

the book has a mass of 2.5 kg. What net force must act on the book to mak it accelerate to the left at a rate of 7.0m/s2?

Reil [10]

Answer:

17.5 N

Explanation:

<h2>Given :</h2>

Mass (m) = 2.5 kg
Acceleration (a) = 7.0 m/s²

<h2>To calculate :</h2>

Force exerted (F)

<h2>Calculation :</h2>

→ F = (2.5 × 7.0) N

→ F = 25/10 × 7 N

→ F = 5/2 × 7 N

→ F = (5 × 7)/2 N

→ F = 35/2 N

→ <u>F</u><u> </u><u>=</u><u> </u><u>1</u><u>7</u><u>.</u><u>5</u><u> </u><u>N</u><u> </u><u>towards</u><u> </u><u>left</u>

Hence, 17.5 N of net force must act on the book to make it accelerate to the left.

5 0

2 years ago

A uniform solid sphere rolls down an incline. A) What must be the incline angle (deg) if the linear acceleration of the center o

Nonamiya [84]

Answer:

a) θ = 12.12°

b) equal to 0.21g

Explanation:

Solution:-

Declare variables:

- The mass of solid sphere, m

- The inclination angle, θ

- The linear acceleration a down the slope of the solid sphere is a = 0.21g

Where, g: The gravitational acceleration constant.

- The component of weight of solid sphere directed down the slope is given by:

Ws = m*g*sin ( θ )

- Apply Newton's second law of motion down the slope, state:

F_net = m*a

- The only net force acting on the solid sphere is the Weight. So, the equation of motion in the coordinate axis ( down the slope ).

Ws = m*a

m*g*sin ( θ ) = m*0.21*g

- Solve for inclination angle ( θ ):

sin ( θ ) = 0.21

θ = arcsin ( 0.21 )

θ = 12.12°

- If a friction-less block of mass ( m ) moves down the same slope then block has weight component down the slope as:

Wb = m*g*sin ( θ )

- Apply Newton's second law of motion down the slope, state:

F_net = m*a

- The only net force acting on the solid sphere is the Weight. So, the equation of motion in the coordinate axis ( down the slope ).

Ws = m*a

m*g*sin ( θ ) = m*a

- Solve for linear acceleration ( a ):

g*sin ( θ ) = a

a = sin ( 12.12 ) * g

a = 0.21g

Answer: The acceleration is independent of mass and only depends on the inclination angle θ.

7 0

4 years ago

A uniform disk is constrained to rotate about an axis passing through its center and perpendicular to the plane of the disk. if

AleksandrR [38]

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8 0

4 years ago

Alex swims at an average speed of 45 m/min. How far does he swim in 1 min 24 secs?

ohaa [14]

Answer:

SOLUTION: Alex swim at an average speed of 45 meters per seconds how far does he swim in 1 minutes and 24 seconds. 1 minute and 24 seconds is 84 seconds. If he swims 45 meters every second and he swims for 84 seconds, that means he swims: 45 * 84 = 3780 meters in 1 minute and 24 seconds.

Explanation:

You multiply 45 by 84 and that is equal to 3,780.

3 0

3 years ago