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gavmur [86]
3 years ago
11

Nahzvsbsnsnsmsskskssks

Physics
2 answers:
Reika [66]3 years ago
6 0
Uhhhh what??????????
prisoha [69]3 years ago
3 0

Answer:

some one might report you

Explanation:

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Momentum=mass X velocity
Sliva [168]

Answer:

Hope it helped

stay safe, mark BRAINLIEST

6 0
2 years ago
A charge if 2 nC is placed 10cm to the right of a conducting sphere with a diameter of 2 cm. A charge of 5 nC is placed 10 nC to
SCORPION-xisa [38]

Answer:

The charge at the center of the conducting sphere is zero.

Explanation:

A principle of conductor materials is that the electric field inside a conductor in electrostatic state is always zero. The gauss law says that the flux of a electric field in a closed surface is proportional to the charge enclosed by the surface. Then if the Electric field inside of a conductor is zero, imperatively the charge anywhere inside the conductor is zero too, so the charge at the center of the sphere is zero.

3 0
3 years ago
How can water be used for energy???
stellarik [79]
<span>by placing dams in tidal areas. ITS  the only one that has anything to do with water</span>
3 0
3 years ago
Read 2 more answers
A 300 kg car travels at 11 ms. What is the momentum
sweet-ann [11.9K]
The momentum of a <span>300 kg car traveling at 11 ms is 3300 ms</span>
5 0
3 years ago
A 12.0-V emf automobile battery has a terminal voltage of 16.0 V when being charged by a current of 10.0 A. (a) What is the batt
forsale [732]

Answer:

(a) the battery’s internal resistance is 0.4 Ω

(b) the dissipated power dissipated inside the battery is 40 W

(c) the  rate 0.096°C/min

Explanation:

Given information:

emf, ε = 12 V

voltage, V = 16 V

current, I = 10 A

mass, m = 20 kg

specific heat, c = 0.300 kcal/kg°C = 1255.8 J/kg°C

(a) What is the battery’s internal resistance?

to calculate the internal resistance, we can calculate by using the following formula

V = ε - Ir

where

V = voltage (V)

I = current (A)

r = internal resistance (Ω)

ε = emf (V)

since the battery is being charged, the current is negative, so

V = ε - (-I) r

V = ε + Ir

r = (V- ε)/I

 = (16 - 12)/10

 = 0.4 Ω

(b) What power is dissipated inside the battery?

to determine the dissipated power in the battery, use the following equation

P = I²r

where

P = power (W)

P = (10)² (0.4)

  = 40 W

(c) At what rate (in °C/min ) will its temperature increase if its mass is 20.0 kg and it has a specific heat of 0.300kcal/kg⋅°C , assuming no heat escapes

to find the rate of temperature increase by

Q = m c ΔT

where

Q = thermal energy (J)

c = specific heat (J/kg°C)

ΔT = the change of temperature

to find the energy, we use

E = Pt

the energy is converted in one minute

E = 40 x 60

  = 2400 J

thus,

2400 = 20 x 1255.8 x ΔT

ΔT = 2400/(20 x 1255.8)

     = 0.096°C/min

3 0
3 years ago
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