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MakcuM [25]
4 years ago
14

Running longer would be an example of how you might improve your running performance

Physics
1 answer:
AURORKA [14]4 years ago
8 0
This is true, however if it wee better worded it would be obvious. This is simply stating that you have a higher endurance which would be a visual improvement in your running performance. Hope this helped <3
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A 500N person stands 2.5m from a wall against which a horizontal beam is attached. The beam is 6m long and weighs 200N. A cable
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PART A)

Here by force balance along Y direction

Tsin45  + F_y = 500 + 200

Force balance along X direction

Tcos45 = F_x

now by torque balance

Tsin45 (6) = 500 (2.5) + 200 (3)

T(4.24) = 1250 + 600

T = 436.3 N

PART B)

now from above equations

Tsin45 + F_y = 700

F_y = 391.5 N

F_x = Tcos45 = 308.5 N

now net reaction force of wall is given as

F = \sqrt{F_x^2 + F_y^2}

F = 498.4 N

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3 years ago
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The length of a force vector represents the
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The length of the segment AB represents the magnitude of the force.

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Electricity is the flow of electrical power or charge.

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A 4.0-mm-diameter hole is 1.0 m below the surface of a 2.0-m-diameter tank of water. What is the rate, in mm/min, at which the w
kykrilka [37]

Answer:

1.06 mm/min

Explanation:

h = height of the water level above the hole = 1 m

d_{h} = diameter of hole = 4 mm = 0.004 m

A_{h} = Area of cross-section of hole = (0.25) \pi d_{h}^{2}

d_{t} = diameter of tank = 2 m

A_{t} = Area of cross-section of tank = (0.25) \pi d_{t}^{2}

R = rate at which the water level drop

Rate at which the water level drop is given as

R = \frac{A_{h} (\sqrt{2gh}))}{A_{t}}

R = \frac{((0.25) \pi d_{h}^{2}) (\sqrt{2gh}))}{((0.25) \pi d_{t}^{2})}

R = \frac{(d_{h}^{2}) (\sqrt{2gh}))}{(d_{t}^{2})}

R = \frac{(0.004)^{2} \sqrt{2(9.8)(1)}}{(2)^{2}}

R = 17.7\times 10^{-6} m/s

R = 0.0177 mm/sec

R = (0.0177) (60) mm/min

R = 1.06 mm/min

8 0
4 years ago
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