Question

What is the electric force between a glass ball that has +4.3 × 10−6 C of charge and a rubber ball that has −5 × 10−6 C of charge when they are separated by a distance of 3.2 cm? The value of the Coulomb constant is 8.98755 × 109 N · m2 /

Answer 1

Answer:

188.7 N

Explanation:

We are given that

$q_1=4.3\times 10^{-6} C$

$q_2=-5\times 10^{-6} C$

$r=3.2 cm=\frac{3.2}{100}=0.032 m$

$1 m=100 cm$

$k=8.98755\times 10^9Nm^2/C^2$

We know that Coulomb's force

$F=\frac{kq_1q_2}{r^2}$

Using the formula

$F=\frac{8.98755\times 10^9\times 4.3\times 10^{-6}\times 5\times 10^{-6}}{(0.032)^2}$

$F=188.7 N$