2 years ago

What is the acceleration of softball if it has a mass of 0.5 kg and hits the catcher's

Physics

1 answer:

lisabon 2012 [21]2 years ago

7 0

Answer:

Your answer is 50m/s^2

Explanation:

A = F/M

25N/0.5kg = 50

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A 1,103 kg car traveling at 18 m/s to the south collides with a 4,919 kg truck that is initially at rest at a stoplight. The car

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ANSWER

$3.30\text{ m/s}$

EXPLANATION

Parameters given:

Mass of car, mc = 1103 kg

Mass of truck, mt = 4919 kg

Initial velocity of car, uc = 18 m/s

Inital velocity of truck = 0 m/s

To solve this problem, we have to apply the law of conservation of momentum, which states that the total momentum of a system is constant.

This implies that:

$m_cu_c+m_tu_t=m_cv_c+m_tv_t$

Since the car and the truck stick together after the collision, they will have the same final velocity.

Hence:

$m_cu_c+m_tu_t=(m_c+m_t)v_{}_{}$

Substitute the given values and solve for v (final velocity):

$\begin{gathered} (1103\cdot18)+(4919\cdot0)=(1103+4919)v \\ \Rightarrow19854=6022v \\ \Rightarrow v=\frac{19854}{6022} \\ v=3.30\text{ m/s} \end{gathered}$

That is the final velocity of the two-vehicle mass.

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