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Gnoma [55]
3 years ago
6

What is the acceleration of softball if it has a mass of 0.5 kg and hits the catcher's

Physics
1 answer:
lisabon 2012 [21]3 years ago
7 0

Answer:

Your answer is 50m/s^2

Explanation:

A = F/M

25N/0.5kg = 50

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A girl is bouncing on a trampoline where is her gravitational potential energy a maximum and where is her kinetic energy maximum
Stella [2.4K]

Answer:

When you jump down, your kinetic is converted to potential energy of the stretched trampoline. The trampoline's potential energy is converted into kinetic energy, which is transferred to you, making you bounce up. At the top of your jump, all your kinetic energy has been converted into potential energy. Right before you hit the trampoline, all of your potential energy has  been converted back into kinetic energy. As you jump up and down your kinetic energy increases and decrease.

7 0
3 years ago
What method would produce disease resistant cattle in the shortest amount of time?
xenn [34]
My brother said it is D
7 0
3 years ago
If a gas has a gage pressure of 156 kPa, it is absolute pressure is approximately
Art [367]
In the given question, one important information for getting to the actual solution is not given and that is the atmospheric pressure. To find the approximate absolute pressure, it is needed to add the value of atmospheric pressure with the gage pressure.
Atmospheric pressure = 100 kPa
Then
Absolute pressure = 156 + 100 kPa
                             = 256 KPa.
5 0
3 years ago
What is the kinetic energy of an automobile with a mass of 1252 kg traveling at a speed of 12 m/s?
torisob [31]
KE = 1/ 2 * 1252 * 144
 as  KE = 1/2 * m * v ^2
 = 90144 J



4 0
3 years ago
A 4.5-kg, three legged stool supports a 89-kg person. If each leg of the stool has a cross-sectional diameter of 2.8 cm and the
kkurt [141]

Answer:

4.96 × 10⁵ Pa

Explanation:

F = mg

F = (m_{person}+m_{stool})g\\\\F =  (4.5 + 89)*9.8\\\\F = 916.3 N

This force is evenly distributed on the three leg

radius, r = d/2

= 2.8 / 2

= 1.4 cm = 0.014 m

total cross sectional area of the three legs, A = 3*pi*r^2

= 3\times\pi \times0.014^2\\\\= 1.847\times10^-^3m^2

Pressure due to weight,

P = Weight/A

P = / 1.847 × 10⁻³\\P = \frac{ 916.3N}{1.847\times10^-^3} \\\\P= 496032.9Pa

P = 4.96 × 10⁵ Pa

8 0
3 years ago
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