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Agata [3.3K]
3 years ago
11

What is my purpose?

Physics
1 answer:
castortr0y [4]3 years ago
8 0
As Rene Descartes - french mathematician of Cartesian graphs - said "Cogito ergo sum". I think, therefore I am. 
This can be adapted to I think therefore I am, I think ... as a "geeky joke".
You might be interested in
Earth orbits the sun once every
Karo-lina-s [1.5K]

Answer:1 trip around the earth is an angular displacement of 2*pi

3.6525*10^2 days

I

Explanation:24 h/1 day * 3.600*10^3 s/1h = 3.156*10^7 s

Angular speed = angular displacement / time

Angular speed = 2*pi rads / 3.156*10^7 s = 1.9910*10^-7 rad/s

3 0
3 years ago
In some plants, the pistils don’t Form until a few days after the stamens do.How might this keep a plant from self pollinating
KATRIN_1 [288]

For a flower to be pollinated, pollen from an anther (which is located at the top of the stamen) needs to reach a stigma (at the top of the pistle.) Some plants are genetically capable of pollinating themselves if their own pollen reaches their own stigma; some plants are not capable of self pollination under any circumstances.

For plants that can genetically self pollinate, but would prefer not to, they can avoid this by having their pistil and pollen/stamens mature at different times. If the stamens mature first, the pollen will be dispersed by animals or wind or whatever dispersal mechanism it relies on. Then by the time the pistil is ready to be pollinated, there is no pollen left in that flower to land on the stigma.

3 0
3 years ago
What is temperature?
FromTheMoon [43]

Answer:

B a measure of the amount of matter in an object

8 0
3 years ago
Question 1 of 10
Novay_Z [31]

Answer:

C. 5.6 × 10^11 N/C

Explanation:

The electric field E at a distance R from a charge Q is given by

E = k\dfrac{Q}{R^2}

where k = 9*10^9Nm/C is the coulomb's constant.

Now, in our case

R = 0.0075m

Q = 0.0035C;

therefore,

E = (9*10^9)\dfrac{0.0035C}{(0.0075m)^2}

\boxed{E = 5.6*10^{11}N/C.}

which is choice C from the options given<em> (at least it resembles it).</em>

6 0
3 years ago
Question 3 Please, i need help! Thank you
Tom [10]
I don't know this 1 I'm sorry I can't help you 
4 0
3 years ago
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