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3 years ago

Manipulate the formula, Q = m • cp • ΔT, to calculate the initial temperature of the metal.

Chemistry

1 answer:

Leya [2.2K]3 years ago

8 0

Answer:

Explanation:

Q = m x cp x ( Final temperature - Initial temperature )

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A.)The equilibrium constant, Kp, for the following reaction is 0.110 at 298 K:

Ainat [17]

<span>PPCl5 = ?? atm hop it helps</span>

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4 years ago

Calculate the concentration of the rubidium hydroxide solution in g dm³. (relative atomic mass: Rb = 85; relative formula mass:

Fofino [41]

Answer:

assalam o aalaikum

Explanation:

180

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-1

Given that 0 find the value of a and the value of b.

(2 marks)

5 0

3 years ago

Name of the the following unsaturated Hydrocarbon

djyliett [7]

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3 years ago

What is the composition, in atom percent, of an alloy that contains a) 45.5 lbm of silver, b) 83.7 lbm of gold, and c) 6.3 lbm o

lyudmila [28]

Answer:

$\% atAg=44.6\%\\\% atAu=44.9\%\\\% atCu=10.5\%$

Explanation:

Hello,

In this case, for computing the atom percent, one must obtain the number of atoms of silver, gold and copper as shown below:

$atomsAg=45.5lbm*\frac{453.59g}{1lbm}*\frac{1molAg}{107.87gAg}*\frac{6.022x10^{23}atomsAg}{1molAg}=1.15x10^{26}atomsAg\\atomsAu=83.7lbm*\frac{453.59g}{1lbm}*\frac{1molAu}{196.97gAu}*\frac{6.022x10^{23}atomsAu}{1molAu}=1.16x10^{26}atomsAu\\atomsCu=6.3lbm*\frac{453.59g}{1lbm}*\frac{1molAg}{63.55gCu}*\frac{6.022x10^{23}atomsCu}{1molCu}=2.71x10^{25}atomsCu$

Thus, the atom percent turns out:

$\% atAg=\frac{1.15x10^{26}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =44.6\%\\\% atAu=\frac{1.16x10^{26}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =44.9\%\\\% atCu=\frac{2.71x10^{25}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =10.5\%$

Best regards.

4 0

3 years ago

Usually hard but brittle<br> Ionic or covalent

aleksandrvk [35]

Answer:

Ionic

Explanation: Ionic compounds tend to be hard and brittle while covalent compounds tend to be softer and more flexible.

Hope this helped!

7 0

3 years ago

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