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jenyasd209 [6]
3 years ago
14

Ten gallons of water is a measurement of its mass. True False

Chemistry
1 answer:
Tems11 [23]3 years ago
4 0

Answer:

True

Explanation:

Its used to measure mass. Ten gallons weigh 8 pounds.

:D

Have a good day flopper :D

<em></em>

<em>*eliza*</em>

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A gas sample occupies 350.0 mL at 546 mm Hg. What volume does the gas occupy at 652 mm Hg?​
leva [86]

Answer:

293.1 mL.

Explanation:

  • Boyle's law states that: at a constant temperature the pressure of a given mass of an ideal gas is inversely proportional to its volume.
  • It can be expressed as: <em>P₁V₁ = P₂V₂,</em>

P₁ = 546.0 mm Hg, V₁ = 350.0 mL.

P₂ = 652.0 mm Hg, V₂ = ??? mL.

<em>∴ V₂ = (P₁V₁)/(P₂)</em> = (546.0 mm Hg)(350.0 mL) / (652.0 mm Hg) = <em>293.1 mL.</em>

8 0
3 years ago
How many moles of water react with 0.946 mol of nitrogen dioxide
VARVARA [1.3K]
<span>the answer is
2.7 moles

</span>
5 0
3 years ago
What is science......?​
den301095 [7]

\huge \underbrace \mathfrak \blue{Answer}

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5 0
3 years ago
Read 2 more answers
What volume of a 0.155 M potassium hydroxide solution is required to neutralize 25.7 mL of a 0.388 M hydrobromic acid solution
vekshin1

Answer: Therefore, the volume of a 0.155 M potassium hydroxide solution  is 56.0 ml

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

M_1 = molarity of HBr solution = 0.338 M

V_1 = volume of HBr solution = 25.7 ml

M_2 = molarity of KOH solution = 0.155 M

V_2 = volume of KOH solution = ?

n_1 = valency of HBr = 1

n_2 = valency of KOH = 1

1\times 0.338\times 25.7=1\times 0.155\times V_2

V_2=56.0ml

Therefore, the volume of a 0.155 M potassium hydroxide solution  is 56.0 ml

8 0
3 years ago
Complete the balanced neutralization equation
lbvjy [14]

Answer:

2 HC₂H₃O₂(aq) + Sr(OH)₂(aq) ⇒ Sr(C₂H₃O₂)₂(aq) + 2 H₂O

Explanation:

Let's consider the reaction between acetic acid and strontium hydroxide. This is a neutralization reaction, in which an acid reacts with a base to form salt and water. The unbalanced equation is:

HC₂H₃O₂(aq) + Sr(OH)₂(aq) ⇒ Sr(C₂H₃O₂)₂(aq) + H₂O

We have 1 acetate ion to the left and 2 to the right, so we will multiply HC₂H₃O₂(aq) by 2.

2 HC₂H₃O₂(aq) + Sr(OH)₂(aq) ⇒ Sr(C₂H₃O₂)₂(aq) + H₂O

Finally, we multiply water by 2 to get the balanced equation.

2 HC₂H₃O₂(aq) + Sr(OH)₂(aq) ⇒ Sr(C₂H₃O₂)₂(aq) + 2 H₂O

8 0
3 years ago
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