Answer:
- 1 mole of carbon disulfide gas at 273 K and 40 L
- 1 mol of chlorine gas at 273 K and 40 L
- 1 mol of neon gas at 273 K and 40 L
- 1 mol of neon gas at 273 K and 20 L
- 1/2 mol of neon gas at 273 K and 20 L
- 1/2 mol of neon gas at 100 K and 20 L
- 1/2 mol of liquid neon at 100 K
Explanation:
Entropy is the measure of disorder or randomness in a closed system. Its an extensive property of a thermodynamic system
The following points must be considered when ranking the systems according to their entropy:
- The entropy of gases are highest than liquids or solid. And entropy of liquid is higher than solid. That is because gas has more microstate thus have the highest entropy.
- Entropies of large complicated molecules are greater than those of smaller, simpler molecules. Because larger molecules have more disorder because of the greater number of ways they can be move around in three dimensional space.
- highest temperature and highest volume will lead to greatest entropy
- 1 mole of any substance will have greater entropy than 1/2 mole of that same substance
Answer: genus
Explanation:
Amoebas do not form a single taxonomic group; instead, they are found in every major lineage of eukaryotic organisms. Amoeboid cells occur not only among the protozoa, but also in fungi, algae, and animals.
(1) False, lots of energy is actually produced from nuclear fuel, if we didn't get much then we probably wouldn't use it
(2) False, its burning coal that contributes to acid rain, since it contains sulfur
(3) False again, we can control the reaction with aptly named control rods, which are typically made of boron, to absorb some of the neutrons flying around in the chain reaction
(4) True, radioactive waste is very difficult to dispose of, and is also very dangerous. Sources of radiation can remain so for millions of years
Answer:
B.They do not react chemically
Explanation:
This is because all noble gases haves full outer shell therefore they don’t participate in bonding.They are referred to as inert which means unreactive.
1) At tne same temperature and with the same volume, initially the chamber 1 has the dobule of moles of gas than the chamber 2, so the pressure in the chamber 1 ( call it p1) is the double of the pressure of chamber 2 (p2)
=> p1 = 2 p2
Which is easy to demonstrate using ideal gas equation:
p1 = nRT/V = 2.0 mol * RT / 1 liter
p2 = nRT/V = 1.0 mol * RT / 1 liter
=> p1 / p2 = 2.0 / 1.0 = 2 => p1 = 2 * p2
2) Assuming that when the valve is opened there is not change in temperature, there will be 1.00 + 2.00 moles of gas in a volumen of 2 liters.
So, the pressure in both chambers (which form one same vessel) is:
p = nRT/V = 3.0 mol * RT / 2liter
which compared to the initial pressure in chamber 1, p1, is:
p / p1 = (3/2) / 2 = 3/4 => p = (3/4)p1
So, the answer is that the pressure in the chamber 1 decreases to 3/4 its original pressure.
You can also see how the pressure in chamber 2 changes:
p / p2 = (3/2) / 1 = 3/2, which means that the pressure in the chamber 2 decreases to 3/2 of its original pressure.
