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3 years ago

0.403 L is equal to: 4.03 mL 40.3 mL 403 mL 4,030 mL

Physics

2 answers:

Tanzania [10]3 years ago

4 0

Answer:

0.403 mL = 403 L

Explanation:

In this question, it is required to convert 0.403 litres to millilitres. We know that the conversion from L to mL is as follows :

1 litre = 1000 millilitres

For converting 0.403 L to ml we need to use above relation.

0.403 L is equal to 0.403 multiplied by 1000 so that we get 403 mL.

So, the correct option is (c) ''403 mL''. Hence, this is the required solution.

Natalija [7]3 years ago

3 0

The answer is 403 ml coz when you divide 0.403 with 1000 ml you get 403 ml

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Explanation:

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3 years ago

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b) The external force does a work of 0.301 joules.

c) The friction force does a work of -0.301 joules.

d) Both normal force and gravity have done a work of 0 joules.

e) The total work done on the crate is 0 joules.

Explanation:

a) As the crate is moving at constant velocity, we know that magnitude of the force done on the crate must be equal to the friction force. Hence, we must use the following formula:

$F = \mu\cdot m\cdot g$ (1)

Where:

$F$ - External force, in newtons.

$\mu$ - Coefficient of kinetic friction, no unit.

$m$ - Mass, in kilograms.

$g$ - Gravity acceleration, in meters per square second.

If we know that $\mu = 0.24$ , $m= 32\,kg$ and $g = 9.807\,\frac{m}{s^{2}}$ , then the external force is:

$F = (0.24)\cdot (32\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$F = 75.317\,N$

The force that the worker must apply has a magnitude of 75.317 newtons.

b) The direction of the force is parallel to the direction of motion. The work done by this force ( $W_{F}$ ), in joules, is determined by this formula:

$W_{F} = F\cdot \Delta s$ (2)

Where $\Delta s$ is the distance travelled by the crate, in meters.

If we know that $F = 75.317\,N$ and $\Delta s = 0.004\,m$ , then the work done by the force is:

$W_{F} = (75.317\,N)\cdot (0.004\,m)$

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The external force does a work of 0.301 joules.

c) The direction of the friction force is antiparallel to the direction of motion. The work done by this force ( $W_{f}$ ), in joules, is determined by this formula: