1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
klemol [59]
3 years ago
15

0.403 L is equal to: 4.03 mL 40.3 mL 403 mL 4,030 mL

Physics
2 answers:
Tanzania [10]3 years ago
4 0

Answer:

0.403 mL = 403 L

Explanation:

In this question, it is required to convert 0.403 litres to millilitres. We know that the conversion from L to mL is as follows :

1 litre = 1000 millilitres

For converting 0.403 L to ml we need to use above relation.

0.403 L is equal to 0.403 multiplied by 1000 so that we get 403 mL.

So, the correct option is (c) ''403 mL''. Hence, this is the required solution.

Natalija [7]3 years ago
3 0
The answer is 403 ml coz when you divide 0.403 with 1000 ml you get 403 ml
You might be interested in
An fm radio station broadcasts at 98. 6 mhz. What is the wavelength of the radiowaves?.
victus00 [196]

The wavelength of the radio waves is 3.04 cm.

<h3>Calculation:</h3>

λf = c

λ = c/f

where,

λ = wavelength

c = speed of light

f = frequency

Given,

f = 98.6 MHz = 98.6 × 10⁶

c = 3 × 10⁸

To find,

λ =?

Put the values in the formula,

λ = c/f

λ = 3 × 10⁸/98.6 × 10⁶

  = 0.0304 × 10²  m

  = 3.04 cm

Therefore, the wavelength of the radio waves is 3.04 cm.

Learn more about the calculation of wavelength here:

brainly.com/question/8422432

#SPJ4

3 0
1 year ago
In a galvanic cell, electrons flow from the ________ to the _______ .
s2008m [1.1K]

Answer:

E.

Explanation:

In a galvanic cell, electrons flow from the anothe to the cathode.

I hope you got the answer

7 0
3 years ago
HELP NOW brainlist I’ll do anything helppoo
Kazeer [188]

Answer:

b

Explanation:

4 0
3 years ago
25 POINTS PLS ANSWER
Olegator [25]

Answer:

A

Explanation:

a statement that can be used to predict the motions of two objects only under special conditions

4 0
3 years ago
When are you most aware of your motion in a moving vehicle: when it is moving steadily in a straight line or when it is accelera
jenyasd209 [6]

Answer:

A) Accelerating. You would not be aware of the motion if you did not look outside the car

Explanation:

Since human cannot sense the motion (unless visually), but the inertia force caused due to the acceleration of the motion. So if you are in a car with constant velocity, there's no acceleration and no inertia force, you would not be able to sense the motion at all unless you look outside.

3 0
2 years ago
Other questions:
  • A girl weighs 200 newtons. How<br> much work does she do<br> climbing 10 meters of steps?
    6·2 answers
  • A speeding car is travelling at a constant 30.0 m/s when it passes a stationary police car. If the police car delays for 1.00 s
    12·1 answer
  • Head gear is required for many sports and can be the most important piece of safety equipment you can have. Question 2 options:
    10·2 answers
  • What are tiny sacs at the end of the bronchioles filled with air called?
    13·1 answer
  • The Apollo Lunar Module was used to make the transition from the spacecraft to the moon's surface and back. Consider a similar m
    15·1 answer
  • Beyond what point must an object be squeezed for it to be a black hole? A : Schwarzschild Radius. B : Crackpoint. C : Event Hori
    10·2 answers
  • Suppose a particle moves along a straight line with velocity v(t)=t2e−2tv(t)=t2e−2t meters per second after t seconds. How many
    13·1 answer
  • (need help) " You make the following measurements of an object: 42kg and 22m^3. What would be the objects density be? Show work
    10·1 answer
  • During take-off a 5kg model rocket, initially at rest, burns fuel for 4.6s causing its speed to increase from rest to 39m/s duri
    9·1 answer
  • 7. When will an object's displacement and distance traveled be different?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!