The 61.0 kg object<span> ... F = (300kg)(6.673×10−11 </span>N m<span>^2 </span>kg<span>^−2)(61kg)/(.225m)^2. F = 2.412e-5 </span>N<span> towards the 495 </span>kg<span> block. </span>b. [195kg] ===.45m ... (b<span>) You cannot achieve this </span>position<span>. For the </span>net force<span> to become zero, one or both of the </span>masses<span> must ...</span>
Answer:
1.7 hours
Explanation:
Time taken in the journey = 3 hours
Distance of the entire journey = 197 miles
Distance travelled on train = x
Distance travelled on bus = 197-x
Average speed of train = 70 mph
Average speed of bus = 60 mph
Time = Distance / Speed
Distance travelled by train = 119 miles
Time taken on train = 119 / 70 = 1.7 hours
Manuel spent 1.7 hours on the train
Max: 152 million km
min 146 million km
The answer is 10.5 kg m/s
Impulse (I) is the multiplication of force (F) and time interval (Δt): I = F · Δt
Force (F) is the multiplication of mass (m) and acceleration (a): F = m · a
Acceleration (a) can be expressed as change in velocity (v) divided by time interval (Δt): a = Δv/Δt
So:
a = Δv/Δt ⇒ F = m · a = m · Δv/Δt
F = m · Δv/Δt ⇒ I = m · Δv/Δt · Δt
Since Δt can be cancelled out, impulse can be expressed as:
I = m · Δv = m · (v2 - v1)
It is given:
m = 1.5 kg
v1 = 15 m/s
v2 = 22 m/s
I = 1.5 · (22 - 15) = 1.5 · 7 = 10.5 kgm/s.
Answer:
322 kJ
Explanation:
The work is the energy that a force produces when realizes a displacement. So, for a gas, it occurs when it expands or when it compress.
When the gas expands it realizes work, so the work is positive, when it compress, it's suffering work, so the work is negative.
For a constant pressure, the work can be calcutated by:
W = pxΔV, where W is the work, p is the pressure, and ΔV is the volume variation. To find the work in Joules, the pressure must be in Pascal (1 atm = 101325 Pa), and the volume in m³ (1 L = 0.001 m³), so:
p = 60 atm = 6.08x10⁶ Pa
ΔV = 82.0 - 29.0 = 53 L = 0.053 m³
W = 6.08x10⁶x0.053
W = 322x10³ J
W = 322 kJ
