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FromTheMoon [43]

3 years ago

10

Four springs are stretched to the same distance from the equilibrium position. The spring constants are listed in the table.

2 answers:

musickatia [10]3 years ago

8 0

Answer:

B.) X,W,Y,Z

Explanation:

The elastic potential energy equation is:

PE = (1/2)*k*x²

where x is distance and k is the spring constant. Then, as k increases, PE also increases, so, the greatest potential energy corresponds to the greatest k, and vice versa.

Natalka [10]3 years ago

4 0

The Hook's law states that F=Ke, where
F⇒force applied to the spring,
e⇒extension of the spring and
K⇒spring constant.
Spring constant determines the strength of the spring. The larger the spring constant the stronger the spring it is.
The list from the greatest to list is:

X, W, Y, Z

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A small 32-kilogram canoe broke free of its dock and is now floating downriver at a speed of 2.5 m/s. What is

marysya [2.9K]

<h3>Answer:</h3>

80 kgm/s

<h3>Explanation:</h3>

<u>We are given;</u>

Mass of the Canoe is 32 kg
Speed of the Canoe is 2.5 m/s

We are required to calculate the momentum of the Canoe?

We need to know that momentum is the product of mass of an object and its speed.

Therefore;

Momentum = Mass × speed

Therefore;

Momentum = 32 kg × 2.5 m/s

= 80 Kgm/s

Thus, the momentum of the Canoe is 80 kgm/s.

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4 years ago

A cube of wood is floating on water. a cube of iron is totally submerged in water. the cubes are equal in volume. which cube has

-BARSIC- [3]

The one that's completely submerged is displacing more water, so the buoyant force on it is greater.

5 0

3 years ago

A rod has a radius of 10 mm is subjected to an axial load of 15 N such that the axial strain in the rod is ????௫ = 2.75*10-6, de

EleoNora [17]

Answer:

Knowing we only have one load applied in just one direction we have to use the Hooke's law for one dimension

ex = бx/E

бx = Fx/A = Fx/π $r^{2}$

Using both equation and solving for the modulus of elasticity E

E = бx/ex = Fx / π $r^{2}$ ex

E = $\frac{15}{pi (10 * 10^{-3})^{2} * 2.75 * 10^{-6} } = 17.368 * 10^{9} Pa = 17.4 GPa$

Apply the Hooke's law for either y or z direction (circle will change in every direction) we can find the change in radius

ey = $\frac{1}{E}$ (бy - v (бx + бz)) = $-\frac{v}{E}$ бx

= $\frac{vFx}{Epir^{2} }$ = $\frac{0.23 * 15}{pi (10 * 10^{-3)^{2} } * 17.362 * 10^{9} } = -0.63 *10^{-6}$

Finally

ey = Δr / r

Δr = ey * r = 10 * $-0.63* 10^{-6} mm = -6.3 * 10^{-6} mm$

Δd = 2Δr = $-12.6 * 10^{-6} mm$

Explanation:

5 0

3 years ago

Which of the following is an obstacle to creating computer-based models for tracking a hurricane?

iren [92.7K]

Answer:

4. All of the above I think, not to sure about 1. but the rest are right so im like 90.99999 percent sure good luck

5 0

3 years ago

Q 28.7: A strip 1.2 mm wide is moving at a speed of 25 cm/s through a uniform magnetic field of 5.6 T. What is the maximum Hall

Zinaida [17]

Answer:the maximum Hall voltage across the strip= 0.00168 V.

Explanation:

The Hall Voltage is calculated using

Vh= B x v x w

Where

B is the magnitude of the magnetic field, 5.6 T

v is the speed/ velocity of the strip, = 25 cm/s to m/s becomes 25/100=0.25m/s

and w is the width of the strip= 1.2 mm to meters becomes 1.2 mm /1000= 0.0012m

Solving

Vh= 5.6T x 0.25m/s x 0.0012m

=0.00168T.m²/s

=0.00168Wb/s

=0.00168V

Therefore, the maximum Hall voltage across the strip=0.00168V

3 0

3 years ago