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dezoksy [38]
3 years ago
14

A rocket with mass m traveling with speed v0 along the x axis suddenly shoots out one-third its mass parallel to the y axis (as

seen from an observer at rest) with speed 2v0. Find the x, y, and z components of the final velocity vector of the remaining 2/3 of the rocket's mass.
Physics
1 answer:
SpyIntel [72]3 years ago
7 0

Answer:

\vec{v}=\frac{3}{2}v_0\hat{i}-v_0\hat{j}+0\hat{k}

Explanation:

Initially the rocket velocity is only on the x-axis. After the rocket suddenly shoots out one-third its mass parallel to the y axis, its velocity is in the x and y axes. Thus, According to momentum conservation principle, we have:

mv_0=\frac{2}{3}mv_{x}\\v_x}=\frac{3}{2}v_0\\\\0=\frac{1}{3}m2v_0+\frac{2}{3}mv_{y}\\v_y=-\frac{2}{3}m(v_0)[\frac{3}{2m}]\\v_y=-v_0\\\\(0)_z=(0)_z\\v_z=0

So, the velocity vector of the remaining rocket's mass is:

\vec{v}=\frac{3}{2}v_0\hat{i}-v_0\hat{j}+0\hat{k}

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In 1986, several robotic spacecrafts were sent into space to study the Halley's Comet. Which of these statements best explains w
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Two 800 cm^3 containers hold identical amounts of a monatomic gas at 20°C. Container A is rigid. Container B has a 100 cm^2 pis
Vikki [24]

Answer:

1) Final Temperature of the gas in A will be GREATER than the temperature in B

2) Diagram of both processes on a single PV has been uploaded below

3) The Initial  pressures in containers A and B is 3039.87 J/liters

4) the final volume of container B is 923.36 cm³

Explanation:

Given that;

Temperature = 20°C = 293 K

mass of piston = 10 kg

Area = 100cm³

Volume V = 800 cm³ = 0.8 L

ideal gas constant R = 8.3 J/K·mol

1)

Final Temperature of the gas in A will b GREATER than the temperature in B

2)

Diagram of both processes on a single PV has been uploaded below,

3)

Initial  pressures in containers A and B

PV = nRT

P = RT/V

we substitute

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P = 3039.87 J/liters

Therefore, The Initial  pressures in containers A and B is 3039.87 J/liters

4)

Given that;

power = 25 W

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the final volume of container B = ?

we know that;

work done = power × time

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375 = 3039.87 ( V₂ - 0.8 )

( V₂ - 0.8 ) = 375 / 3039.87

V₂ - 0.8 = 0.12336

V₂ = 0.12336 + 0.8

V₂ = 0.92336 Litres

V₂ = 923.36 cm³

Therefore, the final volume of container B is 923.36 cm³

7 0
3 years ago
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