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bija089 [108]
2 years ago
9

Help me with physics.....​due right now

Physics
1 answer:
serious [3.7K]2 years ago
3 0

In any case, your mass would be<em> 68 kg </em>no matter what

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Alternative sources of energy include : geothermal
baherus [9]

Answer:

All of the above

Explanation:

The correct answer is option E (All of the above)

All the options are alternative source of energy.

The option given are not the traditional way (energy production from coal) of extracting energy as the loss of natural resources does not take place in these source of energy.

energy extracted from wind,  solar light , hydrogen ,etc are the source of energy  the alternative source of production of energy because do not exploit the natural resources, reduce the carbon emission and energy produced by them is clean energy.

6 0
3 years ago
Which of the following best describes the role of attention from a caregiver on the development of intelligence?
WINSTONCH [101]

A child's IQ may increase with attention from a caregiver" is the one among the following that best describes the role of attention from a caregiver on the development of intelligence. The correct option among all the options that are given in the question is the first option. I hope the answer has helped you.


8 0
3 years ago
Read 2 more answers
• La longitud de un alambre de un sujetador de papel (clip) extendido mide 86 mm. ¿Cuántos sujetadores se pueden obtener de un r
kari74 [83]

Answer:

34883.7

Explanation:

Primero hay que convertir las dos unidades a la misma unidad-cm-

3km- 300000 cm

86mm- 8.6mm

Después hay que dividir

300000/8.6= 34883.7209302 ~ 34883.7

7 0
3 years ago
A paper clip that has a mass of 1.5 grams is thrown into the air and initially has a kinetic energy
Vsevolod [243]

Answer:

v = 4.2 \ m/s

Explanation:

Given data:

Mass of the paper clip, m = 1.5 \ g = 0.0015 \ kg

Kinetic energy, K = 0.013 \ \rm J

Let the velocity of the paper clip when it is thrown be <em>v</em>.

Thus,

K = \frac{1}{2}mv^{2}

0.013 = 0.5 \times 0.0015 \times v^{2}

\Rightarrow \ v = 4.16 \ m/s

v = 4.2 \ m/s.  (rounding to nearest tenth)

3 0
3 years ago
The box leaves position x=0x=0 with speed v0v0. The box is slowed by a constant frictional force until it comes to rest at posit
const2013 [10]

Answer:

fr = ½ m v₀²/x

Explanation:

This exercise the body must be on a ramp so that a component of the weight is counteracted by the friction force.

The best way to solve this exercise is to use the energy work theorem

            W = ΔK

Where work is defined as the product of force by distance

           W = fr x cos 180

The angle is because the friction force opposes the movement

          Δk =K_{f} –K₀

          ΔK = 0 - ½ m v₀²

We substitute

         - fr x = - ½ m v₀²      

           fr = ½ m v₀²/x

8 0
3 years ago
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