Answer:
velocity at the top: 0 m/s
acceleration at the top: -9.8 m/s²
Explanation:
Assuming up is positive and down is negative;
The velocity of the ball at the top of its path will be 0 m/s and the acceleration will be negative.
The velocity is 0 m/s because the ball does not move at the top of its path, and it switches from a positive velocity to a negative velocity. It must go through 0 in order to go from positive to negative.
The acceleration, however, is always negative no matter where the ball is in its motion. This negative acceleration causes the ball to slow down as it reaches the top, and speed up as it reaches the bottom.
<u>Think about it:</u> If there wasn't a negative acceleration, and it was instead 0, the ball would never come back down and instead keep going in a straight line.
Answer:
Synthesis reaction
Explanation:
Synthesis reaction: two or more compounds combine to form one.
A + B → C
Decomposition reaction: one compound forms two or more.
C → A + B
Single replacement reaction: an element in one compound is replaced with another element.
AB + C → AC + B
Double replacement reaction: elements in two compounds replace each other.
AB + CD → AC + BD
Speed is equal to distance traveled divided by the time. So it's 3.5 m/s
Answer:
51 Ω.
Explanation:
We'll begin by calculating the equivalent resistance of R₁ and R₃. This can be obtained as follow:
Resistor 1 (R₁) = 40 Ω
Resistor 3 (R₃) = 70.8 Ω
Equivalent Resistance of R₁ and R₃ (R₁ₙ₃) =?
Since the two resistors are in parallel connection, their equivalent can be obtained as follow:
R₁ₙ₃ = R₁ × R₃ / R₁ + R₃
R₁ₙ₃ = 40 × 70.8 / 40 + 70.8
R₁ₙ₃ = 2832 / 110.8
R₁ₙ₃ = 25.6 Ω
Finally, we shall determine the equivalent resistance of the group. This can be obtained as follow:
Equivalent Resistance of R₁ and R₃ (R₁ₙ₃) = 25.6 Ω
Resistor 2 (R₂) = 25.4 Ω
Equivalent Resistance (Rₑq) =?
Rₑq = R₁ₙ₃ + R₂ (series connection)
Rₑq = 25.6 + 25.4
Rₑq = 51 Ω
Therefore, the equivalent resistance of the group is 51 Ω.
<u>Correct Option:</u>
X shows positive while Y shows negative charges, create the electric field as shown.
<u>Option: D</u>
<u>Explanation:</u>
The idea of an electric field provides a way to define how starlight travels to enter our eyes across huge distances of empty space.The electric field is a quantity of vectors that is present at any point in space. The electric field at a region shows the force that, if put at that position, will operate upon a positive charge device.
The direction of the electric field points directly at a positive point charge, and straight at a negative point charge. The field direction is implemented to the force direction exert on a positive test charge. It is externally from a positive charge and radially in toward a negative point charge.
