Answer:
Forces Due to Friction and Newton's Third Law
The forces on the cart include the forward force the horse exerts on the cart and the backward force due to friction at the ground, acting on the wheels. At rest, or at constant velocity, these two are equal in size, because the acceleration of the cart is zero.
Answer:
Given parameters
Potential difference (V) = 220 V
Power of lamp 1 (P1) = 100 W
Power of lamp 2 (P2) = 60 W
Both the bulbs are connected in parallel. Therefore, the potential difference across each of them will be 220 V, because no division of voltage occurs in a parallel circuit.
We know that
Power = Voltage x Current
P = V x I
I = P/V
Lamp 1:
I1 = P1/V
I1 = 100/220
I1 = 5/11 A
Lamp 2:
I2 = P2/V
I2 = 60/220
I2 = 3/11 A
Net current (I) = I1 + I2
I = 5/11 + 3/11
I = 8/11
I = 0.7273 A
Hence, current drawn from the line is 0.727 A
Explanation:
Hope this helps!
<span>We first calculate the velocity of the ball when it hits the ground; this is equal to the square root of the quantity (2*g*d) where g is the acceleration of gravity (9.8 m/s^2) and d is the distance fallen, 1.5m.
So, we get a velocity of sqrt(2*9.8*1.5) = 5.42 m/s.
We can calculate the impulse force applied to the putty ball by using Newton's second law, which states that the applied force is equal to the product of mass and acceleration, where acceleration can be further decomposed as the change in velocity divided by the change in time. Thus, inputting the known values, we have:
F = ma = m(dv/dt) = 1.0*5.42/0.045 = 120.4 newtons.</span>
