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Nataly_w [17]
3 years ago
5

Why is it important to have a control group in a experiment?

Physics
2 answers:
goldenfox [79]3 years ago
5 0
You would compare the results from the experimental group with the results of the control group to see what happens when you change the variable you want to examine. A control group is an essential part of an experiment because it allows you to eliminate and isolate these variables.
Hopefully this helped.
zysi [14]3 years ago
4 0

Answer:it allows you to eliminate and isolate variables.

Explanation:

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1. Approximately how many people watch the March Madness tournament? There are more than 140 million that watch March Madness.
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A freely suspended bar magnet always shows north and south direction why​
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<h2>Answer:</h2>

The earth behaves as a magnetic dipole. Therefore a freely suspended magnet always points towards in the north-south direction because the north pole of the suspended magnet attracts the south pole of the earth's magnet which is the geographical north pole of the earth.

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The density of glycerin is 1.26 g/cm3. Which substance will sink in glycerin?
Mademuasel [1]
The answer to your question is aluminum.
7 0
3 years ago
Read 2 more answers
Which of the following is the best example of a heat conductor?
natka813 [3]

Answer:

<h3>Anything with a dark shade in color and with no reflective surface or any metal</h3>

Explanation:

In this case, a dark shirt or blanket would be a heat conductor as well as metal would be, too

4 0
3 years ago
A ball is shot from the ground straight up into the air with initial velocity of 42 ft/sec. Assuming that the air resistance can
Volgvan

Answer:

Maximum height of the ball, h(t) = 27.56 m

Explanation:

It is given that, a ball is shot from the ground straight up into the air with initial velocity of 42 ft/sec.      

The height of the ball as a function of time t is given by :

h(t)=h_o+v_ot-16t^2

h₀ is initial height, h₀ = 0

So, h(t)=42t-16t^2 .........(1)

For maximum/minimum height,  \dfrac{dh(t)}{dt}=0

42-32t=0...(2)

t = 1.31 s

Differentiating equation (2) wrt t

h''(t) = -32 < 0

So, at t = 1.31 seconds we will get the maximum height.

Put the value of t in equation (1)

h(t)=42\times 1.31-16\times (1.31)^2

h(t) = 27.56 m

Hence, this is the required solution.

7 0
4 years ago
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