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3 years ago

Why is it important to have a control group in a experiment?

2 answers:

5 0

You would compare the results from the experimental group with the results of the control group to see what happens when you change the variable you want to examine. A control group is an essential part of an experiment because it allows you to eliminate and isolate these variables.
Hopefully this helped.

zysi [14]3 years ago

4 0

Answer:it allows you to eliminate and isolate variables.

Explanation:

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3. A 0.35 kg puck slides across the ice with an average force of friction of 0.15 N acting on it. It slides 82 m before coming t

sattari [20]

Answer:

Work done is 12.3 J

Explanation:

We have,

Mass of puck, m = 0.35 kg

Force of friction acting on the puck when it slides is 0.15 N

Distance travelled by the puck is 82 m.

It is required to find the work done on the puck. Finally the puck comes to rest and the force of friction is acting on it. It means the applied force is 0.15 N. Work done is given by

$W=Fd\\\\W=0.15\times 82\\\\W=12.3\ J$

The work done on the puck is 12.3 J.

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4 years ago

What causes an increase in momentum

sergij07 [2.7K]

I honestly don’t know

7 0

3 years ago

Read 2 more answers

Even though I answered this question all I just want to make sure

EastWind [94]

yes this is correct good job

4 0

3 years ago

Read 2 more answers

Black holes are highly condensed remnants of stars. Some black holes, together with a normal star, form binary systems. In such

borishaifa [10]

$\lambda_\text{max} = 2.63\times 10^{-9}\;\text{m}$ .

<h3>Explanation</h3>

The peak emission wavelength of an object depends on its absolute temperature.

$\lambda_\text{max} = \dfrac{2.90\times 10^{-3}}{T}$ ,

where

$\lambda_\text{max}$ is the wavelength in meters where the emission is the strongest.
$T$ is the temperature of the object in degrees Kelvins.

For the gas falling into the black hole,

$T = 1.10\times 10^{6}\;\text{K}$ .

Apply the formula:

$\lambda_\text{max} = \dfrac{2.90\times 10^{-3}}{T} = \dfrac{2.90\times 10^{-3}}{1.10\times 10^{6}} = 2.64\times 10^{-9}\;\text{m} = 2.64 \;\text{nm}$ .

The question mentioned that $\lambda_\text{max}$ is in the X-ray region of the electromagnetic spectrum. According to Encyclopedia Britannica, the wavelength of X-rays range from $10^{-8}\;\text{m}=10\;\text{nm}$ to $10^{-10}\;\text{m} = 0.1\;\text{nm}$ , which indeed includes $2.64\times 10^{-9}\;\text{m} = 2.64 \;\text{nm}$ .

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3 years ago

How is using a digital signal like turning on and off a regular light<br> switch?

Orlov [11]

Answer:

they both use 1 and 0

Explanation:

Flipping a switch shows I for light on and 0 for light off

8 0

3 years ago