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Arte-miy333 [17]
3 years ago
6

A positive charge is moved from one point to another point along an equipotential surface. The work required to move the charge:

______.
a. is positive.
b. is zero.
c. is negative.
d. depends on the magnitude of the potential.
e. depends on the sign of the potential.
Physics
1 answer:
liberstina [14]3 years ago
7 0

Answer:

b . is zero.

Explanation:

An Equipotential surface is the one that has electric potential same throughout the surface. The formula for work done in an electric field is given by

dW= qdV

Now, in an Equipotential surface dV= 0.

Hence the work done in moving a charge from one place to the other in an electric field is zero.

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\Delta W=\Delta K\\\\\int_{0.4}^\infty Fdr=\frac{1}{2}m[v^2-v_o^2]\\\\F=k\frac{Q^2}{r^2}\\\\v_o=0m/s\\\\m=0.08kg\\\\kQ^2\int_{0.4}^{\infty} \frac{dr}{r^2}=kQ^2[-\frac{1}{r}]_{0.4}^{\infty}=\frac{kQ^2}{0.4m}=\frac{(8.98*10^9Nm^2/C^2)(50*10^{-6}C)^2}{0.4m}\\\\kQ^2\int_{0.4}^{\infty} \frac{dr}{r^2}=56.125J

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Next, you equal the total work to the change in K:

\frac{1}{2}mv^2=56.125J\\\\v=\sqrt{\frac{2(56.125J)}{m}}=\sqrt{\frac{2(56.125J)}{0.08kg}}=37.45\frac{m}{s}

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