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Arte-miy333 [17]
2 years ago
6

A positive charge is moved from one point to another point along an equipotential surface. The work required to move the charge:

______.
a. is positive.
b. is zero.
c. is negative.
d. depends on the magnitude of the potential.
e. depends on the sign of the potential.
Physics
1 answer:
liberstina [14]2 years ago
7 0

Answer:

b . is zero.

Explanation:

An Equipotential surface is the one that has electric potential same throughout the surface. The formula for work done in an electric field is given by

dW= qdV

Now, in an Equipotential surface dV= 0.

Hence the work done in moving a charge from one place to the other in an electric field is zero.

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To answer this question we first need to know the distance from the crash to the swimmer and the dock.

The distance is given by:

d=vt

This means that the distance from the crash to the swimmer is:

d=(1450)(3.5)=5075

Therefore the crash happened at 5075 meters from the swimmer.

Now, to determine the time it takes the sound to reach the deck we need to determine the speed of sound on air at that temperature, this is given by:

v=331\sqrt[]{1+\frac{T}{273}}

then if the temperature is 20°C we have:

v=331\sqrt[]{1+\frac{20}{273}}=342.91

Then it takes the sound to reach the deck:

t=\frac{5075}{342.91}=14.8

Finally to determine the time it takes after you hear it we subtract the time it takes for you to hear it, then:

14.8-3.5=11.3

Therefore your friend hear the crash 11.3 seconds after you do.

8 0
1 year ago
A bicyclist on an old bike (combined mass: 92 kg) is rolling down (no pedaling or braking) a hill of height 120 m. Over the cour
Finger [1]

Answer:

V = 48.49m/s

Explanation:

Given the following information:

Combined mass = 92kg

Hill's height = 120m

Course of ride = 384m

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Since we are looking for her speed at the bottom,

Time = distance/speed = 384m/9m.s

Time = 42.67s

we use the equation

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Therefore, plugging the values we have

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V² = 9.8×120×2

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Answer:

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Explanation:

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2 years ago
Which statement about the greenhouse effect is NOT true?.
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2 years ago
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If the brakes are applied and the speed of the car is reduced to 12 m/s in 15 s , determine the constant deceleration of the car
zavuch27 [327]

Given:

\triangle v = 12 m/s

Time = 15 s

To find:

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Formula used:

Deceleration is given by,

a = \frac{\triangle v}{t}

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