CHECK COMPLETE QUESTION BELOW
you stood on a planet having a mass four times that of earth mass and a radius two times of earth radius , you would weigh?
A) four times more than you do on Earth.
B) two times less than you do on Earth.
C) the same as you do on Earth
D) two times more than you do on Earth
Answer:
OPTION C is correct
The same as you do on Earth
Explanation :
According to law of gravitation :
F=GMm/R^2......(a)
F= mg.....(b)
M= mass of earth
m = mass of the person
R = radius of the earth
From law of motion
Put equation b into equation a
mg=GMm/R^2
g=GMm/R^2
g=GM/R^2
We know from question a planet having a mass four times that of earth mass and a radius two times of earth radius if we substitute we have
m= 4M
r=(2R)^2=4R^2
g= G4M/4R^2
Then, 4in the denominator will cancel out the numerator we have
g= GM/R^2
Therefore, g remain the same
Perilymph of scala vestibule; endolymph of cochlear duct; perilymph of scala tympani
Answer:
The force F is created by the reaction of the Earth to the thrust of the rods, whereby the thrust is created by a force of action and reaction.
Explanation:
To answer this question, let's write Newton's second law of the two axes
Y Axis
Fy + N - W = 0
Fy + N = W
X axis
Fx - fr = 0
Fx = fr
The force F is created by the reaction of the Earth to the thrust of the rods, whereby the thrust is created by a force of action and reaction.
The direction of this force is along the length of the rods that are in an Angle, where the x and y components of the force come from
In general this force is small because the rubbing of the skis is small
Answer:
115 kPa
Explanation:
Use Bernoulli equation:
P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂
Assuming no elevation change, h₁ = h₂.
P₁ + ½ ρ v₁² = P₂ + ½ ρ v₂²
Plugging in values:
(582,000 Pa) + ½ (1000 kg/m³) (1.28 m/s)² = P + ½ (1000 kg/m³) (30.6 m/s)²
P = 115,000 Pa
P = 115 kPa
Answer:
Explanation:
Kinematics equation for first Object:
but:
The initial velocity is zero
it reach the water at in instant, t1, y(t)=0:
Kinematics equation for the second Object:
The initial velocity is zero
but:
it reach the water at in instant, t2, y(t)=0. If the second object is thrown 1s later, t2=t1-1=1.02s
The velocity is negative, because the object is thrown downwards
