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2 years ago

How many joules are utilized when warming 5g of steam from 100°C to 120°C?

Physics

1 answer:

soldi70 [24.7K]2 years ago

4 0

Answer:

Q=mc(T2-T1)

Explanation:

Ti is the temperature

m is mass

c is specific heat capacity for steam

Q is heat, [Q]=J

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Electrons move from negative to positive while the voltage flows ________ to _______ .

Sedaia [141]

Answer:

positive to negative.

3 0

2 years ago

A mass m at the end of a spring oscillates with a frequency of 0.89 hz. when an additional 603 g mass is added to m, the frequen

MrMuchimi

The solution for this problem:

Given:

f1 = 0.89 Hz

f2 = 0.63 Hz

Δm = m2 - m1 = 0.603 kg

The frequency of mass-spring oscillation is:
f = (1/2π)√(k/m)
k = m(2πf)²

Then we know that k is constant for both trials, we have:
k = k

m1(2πf1)² = m2(2πf2)²

m1 = m2(f2/f1)²

m1 = (m1+Δm)(f2/f1)²

m1 = Δm/((f1/f2)²-1)

m 1 = 0.603/ (0.89/0.63)^2 – 1

= 0.609 kg or 0.61kg or 610 g

5 0

2 years ago

Select all the correct ANSWERS.

MissTica

The ground exerts an equal force on the golf ball.

3 0

3 years ago

A plank of length L=2.200 m and mass M=4.00 kg is suspended horizontally by a thin cable at one end and to a pivot on a wall at

baherus [9]

Hello!

Let's begin by doing a summation of torques, placing the pivot point at the attachment point of the rod to the wall.

$\Sigma \tau = 0$

We have two torques acting on the rod:
- Force of gravity at the center of mass (d = 0.700 m)

- VERTICAL component of the tension at a distance of 'L' (L = 2.200 m)

Both of these act in opposite directions. Let's use the equation for torque:
$\tau = r \times F$

Doing the summation using their respective lever arms:

$0 = L Tsin\theta - dF_g$

$dF_g = LTsin\theta$

Our unknown is 'theta' - the angle the string forms with the rod. Let's use right triangle trig to solve:

$tan\theta = \frac{H}{L}\\\\tan^{-1}(\frac{H}{L}) = \theta\\\\tan^{-1}(\frac{1.70}{2.200}) = 37.69^o$

Now, let's solve for 'T'.

$T = \frac{dMg}{Lsin\theta}$

Plugging in the values:
$T = \frac{(0.700)(4.00)(9.8)}{(2.200)sin(37.69)} = \boxed{20.399 N}$

3 0

1 year ago

Change of 5000 c flows through a circuit in one hour. what is the current intensity?

AleksandrR [38]

Answer:

I = 1.38 A

Explanation:

Given that,

Charge, q = 5000 C

Time, t = 1 hour = 3600 s

We need to find the current intensity. The current intensity is equal to the electric charge per unit time. It can be given by :

$I=\dfrac{q}{t}$

Substitute all the values in the above formula

$I=\dfrac{5000\ C}{3600\ s}\\\\=1.38\ A$

So, the current intensity is 1.38 A.

8 0

2 years ago