The mass of the large truck is determined as 5680 kg.
<h3>Mass of the truck</h3>
The mass of the truck is calculated as follows;
P = mv
where;
- P is momentum
- m is mass
- v is velocity
m = P/v
m = 125000/22
m = 5680 kg
Thus, the mass of the large truck is determined as 5680 kg.
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Answer:
The capacitance is cut in half.
Explanation:
The capacitance of a plate capacitor is directly proportional to the area A of the plates and inversely proportional to the distance between the plates d. So if the distance was doubled we should expect that the capacitance would be cut in half. That can be verified by the following equation that is used to compute the capacitance in such cases:
C = (\epsilon)*(A/d)
Where \epsilon is a constant that represents the characteristics for the insulator between the plates. A is the area of the plates and d is the distance between them. When we double d we have a new capacitance, given by:
C_new = (\epsilon)*(A/2d)
C_new = (1/2)*[(\epsilon)*(A/d)]
Since C = (\epsilon)*(A/d)] we have:
C_new = (1/2)*C
Answer:
The final charges of each sphere are: q_A = 3/8 Q
, q_B = 3/8 Q
, q_C = 3/4 Q
Explanation:
This problem asks for the final charge of each sphere, for this we must use that the charge is distributed evenly over a metal surface.
Let's start Sphere A makes contact with sphere B, whereby each one ends with half of the initial charge, at this point
q_A = Q / 2
q_B = Q / 2
Now sphere A touches sphere C, ending with half the charge
q_A = ½ (Q / 2) = ¼ Q
q_B = ¼ Q
Now the sphere A that has Q / 4 of the initial charge is put in contact with the sphere B that has Q / 2 of the initial charge, the total charge is the sum of the charge
q = Q / 4 + Q / 2 = ¾ Q
This is the charge distributed between the two spheres, sphere A is 3/8 Q and sphere B is 3/8 Q
q_A = 3/8 Q
q_B = 3/8 Q
The final charges of each sphere are:
q_A = 3/8 Q
q_B = 3/8 Q
q_C = 3/4 Q
Ans: a = 2.50 m/s^2
Explanation:
First convert the mass in its standard unit i.e. kilogram(kg):
2250 lbs = 1020.583kg
Next use Newton's Second law:
F = ma
Where F = 2552N
m = 1020.583kg
=> a = (2552/1020.583)
a = 2.50 m/s^2
Answer:
28716.4740661 N
1.2131147541 m/s
51.2474965841%
Explanation:
m = Mass of plane = 74000 kg
s = Displacement = 3.7 m
f = Frictional force = 14000 N
t = Time taken = 6.1 s
u = Initial velocity = 0
v = Final velocity
Force is given by
The force with which the team pulls the plane is 28716.4740661 N
The speed of the plane is 1.2131147541 m/s
Kinetic energy is given by
Work done is given by
The fraction is given by
The teams 51.2474965841% of the work goes to kinetic energy of the plane.
