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netineya [11]
2 years ago
7

What would life be like if we couldn’t change reaction rates?

Chemistry
1 answer:
Aleksandr-060686 [28]2 years ago
5 0

Answer: if a biochemical reaction in our body is too fast or too slow it can endanger our life.

Explanation:in other example ,rate of reaction is obviously very important to the chemical industry. The rate of reaction dictates the rate of production our daily products.

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Exposure to what type of radiant energy is sensed by human skin as warmth?
larisa86 [58]
The answer is C.gamma rays
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3 years ago
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Suppose that 0.1000 mole each of H2and I2are placed in a 1.000-L flask, stoppered, and the mixture is heated to 425oC. At equili
Katen [24]

<u>Answer:</u> The value of equilibrium constant for the given reaction is 56.61

<u>Explanation:</u>

We are given:

Initial moles of iodine gas = 0.100 moles

Initial moles of hydrogen gas = 0.100 moles

Volume of container = 1.00 L

Molarity of the solution is calculated by the equation:

\text{Molarity of solution}=\frac{\text{Number of moles}}{\text{Volume}}

\text{Molarity of iodine gas}=\frac{0.1mol}{1L}=0.1M

\text{Molarity of hydrogen gas}=\frac{0.1mol}{1L}=0.1M

Equilibrium concentration of iodine gas = 0.0210 M

The chemical equation for the reaction of iodine gas and hydrogen gas follows:

                         H_2+I_2\rightleftharpoons 2HI

<u>Initial:</u>                0.1    0.1

<u>At eqllm:</u>          0.1-x   0.1-x   2x

Evaluating the value of 'x'

\Rightarrow (0.1-x)=0.0210\\\\\Rightarrow x=0.079M

The expression of K_c for above equation follows:

K_c=\frac{[HI]^2}{[H_2][I_2]}

[HI]_{eq}=2x=(2\times 0.079)=0.158M

[H_2]_{eq}=(0.1-x)=(0.1-0.079)=0.0210M

[I_2]_{eq}=0.0210M

Putting values in above expression, we get:

K_c=\frac{(0.158)^2}{0.0210\times 0.0210}\\\\K_c=56.61

Hence, the value of equilibrium constant for the given reaction is 56.61

6 0
3 years ago
"You measure 48.9 mL of a solution of sulfuric acid with an unknown concentration, and carefully titrate this solution using a 1
Blizzard [7]

Answer:

C= 0.532M

Explanation:

The equation of reaction is

H2SO4 + 2KOH = K2SO4+ H2O

nA= 1, nB= 2, CA= ?, VA= 48.9ml, CB= 1.5M, VB= 34.7ml

Applying

CAVA/CBVB = nA/nB

(CA× 48.9)/(1.5×34.7)= 1/2

Simplify

CA= 0.532M

6 0
3 years ago
Science help please 20 points
cupoosta [38]

Answer:

1. Earth

2. Sun

3. Sun

4. Earth

5. Earth

6.Sun

7. Earth

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I'm a lil sus of 3 and 6 but I'm pretty sure it's right.

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2 years ago
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How many moles are in 25kg of Fe2O3?
expeople1 [14]

Answer:

The answer is 159.6882.

Assuming you are converting between grams Fe2O3 and mole.

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