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OLEGan [10]
3 years ago
14

Can someone please HELP?!

Physics
1 answer:
Delicious77 [7]3 years ago
4 0

Answer: a

Explanation: because both B and c are larger than a

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A student is about to sled down a hill. He stands on a hill which is 30 meters tall and he weighs 40kg what is his GPE
PolarNik [594]

Answer:

11760J

Explanation:

Given parameters:

Height of hill  = 30m

Weight  = 40kg

Unknown:

Gravitational potential energy  = ?

Solution:

To find the gravitational potential energy, it is the energy due to the position of a body;

     G.PE  = mgh

m is the mass

g is the acceleration due to gravity

h is the height

 Now insert the parameters and solve;

      G.PE = 40 x 9.8 x 30  = 11760J

3 0
3 years ago
A shot putter shoots a 7.3kg shot from rest to 14m/s in 1.5s. what was the average power?
sweet [91]

Answer: 477W

Explanation:

Given the following :

Mass (m) = 7.3kg

Initial Velocity (u) = 0

Final velocity (v) = 14m/s

time (t) = 1.5s

Power = workdone (W) / time (t)

The workdone can be calculated as the change in kinetic energy (KE) :

Recall ;

KE = 0.5mv^2

Therefore, change in KE is given by:

0.5mv^2 - 0.5mu^2

Change in KE = 0.5(7.3)(14^2) - 0.5(7.3)(0^2)

Change in KE = 715.4J

Therefore ;

Average power = Workdone / time

Workdone = change in KE = 715.4N

Average power = 715.4 / 1.5

Average power = 476.93333 W

= 477W

5 0
4 years ago
PLEASE HELP WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
iVinArrow [24]

Answer:

D

D

C

C

Explanation: BRAINLIEST ME

6 0
3 years ago
What type of thermal transfer happens as waves of infrared radiation?
Mkey [24]
The hotter an object is, the more infrared radiation it emits. Infrared radiation is a type of electromagnetic radiation, which involves waves rather than particles. This means that, unlike conduction and convection, radiation can even pass through the vacuum of space.
5 0
3 years ago
A car driving on a straight track accelerates at a rate of 3.2 m/s^2 for 14 sec. If the initial velocity of the car was 5.1 m/s,
Andreyy89

The final position of the car is 385 m.

Explanation:

We know the formula :

                                   s = ut +  \frac{1}{2} at^{2}

where,

                                     s = distance

                                     u = initial velocity = 5.1 m/s

                                      t = time taken = 14 sec

                                     a = acceleration = 3.2 m/s^{2}

Solving:

                         s = 5.1* 14 + \frac{1}{2} * 3.2 * 14^{2}

                      ∴ s = 385 m

Hence the final position of the car is 385 m.

3 0
3 years ago
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