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Damm [24]
3 years ago
11

A car driving on a straight track accelerates at a rate of 3.2 m/s^2 for 14 sec. If the initial velocity of the car was 5.1 m/s,

and its initial position was 0 m, what is its final position?
-385m
32m
385m
242.2m
-242.2m
Physics
1 answer:
Andreyy893 years ago
3 0

The final position of the car is 385 m.

Explanation:

We know the formula :

                                   s = ut +  \frac{1}{2} at^{2}

where,

                                     s = distance

                                     u = initial velocity = 5.1 m/s

                                      t = time taken = 14 sec

                                     a = acceleration = 3.2 m/s^{2}

Solving:

                         s = 5.1* 14 + \frac{1}{2} * 3.2 * 14^{2}

                      ∴ s = 385 m

Hence the final position of the car is 385 m.

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