A conducting sphere is charged up such that the potential on its surface is 100 V (relative to infinity). If the sphere's radius
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Answer:
-0.020475 V
Explanation:
= Vacuum permeability =
= Number of turns of coil = 25
= Number of turns of coil 2 = 300
= Rate of current increased =
d = Diameter = 2 cm
r = Radius =
A = Area =
Magnetic field in the solenoid is given by
Magnetic flux is given by
The average magnetic flux through each turn of the inner solenoid is
Mutual inductance is given by
The mutual inductance of the two solenoids is
Induced emf is given by
The emf induced in the outer solenoid by the changing current in the inner solenoid is -0.020475 V
Given:
F = ax
where
x = distance by which the rubber band is stretched
a = constant
The work done in stretching the rubber band from x = 0 to x = L is
![W=\int_{0}^{L} Fdx = \int_{0}^{L}ax \, dx = \frac{a}{2} [x^{2} ]_{0}^{L} = \frac{aL^{2}}{2}](https://tex.z-dn.net/?f=W%3D%5Cint_%7B0%7D%5E%7BL%7D%20Fdx%20%3D%20%5Cint_%7B0%7D%5E%7BL%7Dax%20%5C%2C%20dx%20%3D%20%5Cfrac%7Ba%7D%7B2%7D%20%20%5Bx%5E%7B2%7D%20%5D_%7B0%7D%5E%7BL%7D%20%3D%20%20%5Cfrac%7BaL%5E%7B2%7D%7D%7B2%7D%20)
Answer:
F = ax
where
x = distance by which the rubber band is stretched
a = constant
The work done in stretching the rubber band from x = 0 to x = L is
Answer: