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Law Incorporation [45]
3 years ago
12

One of the challenges of wind power is _____. the location of wind farms the ongoing cost of wind power that it adds carbon to t

he atmosphere as global warming increases, the wind will diminish
Physics
2 answers:
Mila [183]3 years ago
5 0
I think the correct answer from the choices listed above is the first option. One of the challenges of wind power is the <span>location of wind farms. Wind farms require large areas in order to function.  It consumes a lot of space. Hope this answers the question.</span>
Kay [80]3 years ago
3 0
<h3><u>Answer;</u></h3>

The location of wind farms

<h3><u>Explanation;</u></h3>

-<em><u>Wind power involves use of wind to generate electricity or mechanical power.</u></em> This happens when wind is used to turn blades then the turning blades spin a shaft connected to generator which converts kinetic energy to electrical energy.

-<em>Despite the advantages of wind such as little impact on environment, it has a number of challenges which includes;</em>

  • <em>Wind power is not as cost effective as fossil fuels.  </em>
  • <em>Noise pollution which has impact on birds </em>
  • <em>Other needs for land than energy generation </em>
  • <u><em>Wind sites are located far from urban areas, making it more expensive to transfer energy farther.</em></u>
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A frog is at the bottom of a 17-foot well. Each time the frog leaps, it moves up 3 feet. If the frog has not reached the top of
docker41 [41]

Answer:

The frog takes 8 jumps to reach top of well

Explanation:

Given data

Frog at bottom=17 foot

Each time frog leaps 3 feet

Frog has not reached the top of the well, then the frog slides back 1 foot

To Find

Total number of leaps the frog needed to escape from well

Solution

in 1 jump distance jumped=3+(-1)

                                           =2 feet

                                           =2×1 feet

The "-1" is because the frog goes back

Now After 2 jumps the distance jumped as:

                     Distance Jumped=2+2

                     Distance Jumped=2*2

                                                   =4 feet

Similarly after 7 jumps

                    Distance Jumped=2+2+......+2

                    Distance Jumped=2*7

                                                 =14 feet

Now after 8th jump the frog climbs but doesnot slide back as it is reached to the top of well.

So

              Distance Jumped=(Distance Jumped after 7 jumps)+3

                                           =14+3

                                           =17 feet

The frog takes 8 jumps to reach top of well                

7 0
3 years ago
3. Discuss the main purpose of Experiment" Explain the greatest advantage of experiment in psychology?
Scrat [10]

Answer:

Social psychologists utilize experimental techniques to study how people are influenced by groups. Health psychologists rely on experimentation and research to better understand the factors that contribute to wellness and disease.

Explanation:

7 0
3 years ago
At a place where an object is thrown vertically downward with a speed of while a different object is thrown vertically upward wi
Bumek [7]

Answer:

Both objects will undergo the same change in velocity

Explanation:

m = Mass of the Earth =  5.972 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Radius of Earth = 6371000 m

m = Mass of object

Any object which is falling has only the acceleration due to gravity.

ma=\dfrac{GMm}{r^2}\\\Rightarrow a=\dfrac{GM}{r^2}\\\Rightarrow a=\dfrac{6.67\times 10^{-11}\times 5.972\times 10^{24}}{(6.371\times 10^6)^2}\\\Rightarrow a=9.81364\ m/s^2

The acceleration due to gravity on Earth is 9.81364 m/s²

So, the speeds of the objects will change at an equal rate of 9.81364 m/s² but the change will be negative when an object is thrown up.

Hence, both objects will undergo the same change in velocity.

4 0
3 years ago
A thin hoop is hung on a wall, supported by a horizontal nail. The hoop's mass is M=2.0 kg and its radius is R=0.6 m. What is th
boyakko [2]

Answer:

Explanation:

Given that,

Mass of the thin hoop

M = 2kg

Radius of the hoop

R = 0.6m

Moment of inertial of a hoop is

I = MR²

I = 2 × 0.6²

I = 0.72 kgm²

Period of a physical pendulum of small amplitude is given by

T = 2π √(I / Mgd)

Where,

T is the period in seconds

I is the moment of inertia in kgm²

I = 0.72 kgm²

M is the mass of the hoop

M = 2kg

g is the acceleration due to gravity

g = 9.8m/s²

d is the distance from rotational axis to center of of gravity

Therefore, d = r = 0.6m

Then, applying the formula

T = 2π √ (I / MgR)

T = 2π √ (0.72 / (2 × 9.8× 0.6)

T = 2π √ ( 0.72 / 11.76)

T = 2π √0.06122

T = 2π × 0.2474

T = 1.5547 seconds

T ≈ 1.55 seconds to 2d•p

Then, the period of oscillation is 1.55seconds

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3 years ago
If we've traveled with medium and displaces the particles perpendicular to the direction in which the wave is traveling. This ty
AlexFokin [52]
This type of wave is a transverse wave, or an S wave (secondary wave)
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