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4 years ago

What is the shape of the orbit of satellites

2 answers:

8 0

Every closed orbit is an ellipse.

If the big body just bends the small body's path but doesn't capture it, then the small body's path is a hyperbola.

dem82 [27]4 years ago

4 0

Answer:

The shape will be elliptical hopefully this helps!

You might be interested in

How does the physical structure of a plant have Large leaves help it survive?

elena-14-01-66 [18.8K]

The large leaves help it survive as they serve as the organ for photosynthesis.

Explanation:

Photosynthesis, the process by which green plants and certain other organisms transform light energy into chemical energy.
During photosynthesis in green plants, light energy is captured and used to convert water, carbon dioxide, and minerals into oxygen and energy-rich organic compounds

Leaves provide food and air to help a plant stay healthy and grow. Through photosynthesis, leaves turn light energy into food.
Through pores, or stomata, leaves breathe in carbon dioxide and breathe out oxygen. Leaves also release excess water.
Most leaves are broad and so have a large surface area allowing them to absorb more light
A thin shape means a short distance for carbon dioxide to diffuse in and oxygen to diffuse out easily.
The exchange of oxygen and carbon dioxide in the leaf occurs through pores called stomata.
Normally stomata open when the light strikes the leaf in the morning and close during the night.

3 0

3 years ago

The frequency of a physical pendulum comprising a nonuniform rod of mass 1.15 kg pivoted at one end is observed to be 0.658 Hz.

S_A_V [24]

Answer:

The rotational inertia of the pendulum around its pivot point is $0.280\,kg\cdot m^{2}$ .

Explanation:

The angular frequency of a physical pendulum is measured by the following expression:

$\omega = \sqrt{\frac{m\cdot g \cdot d}{I_{o}} }$

Where:

$\omega$ - Angular frequency, measured in radians per second.

$m$ - Mass of the physical pendulum, measured in kilograms.

$g$ - Gravitational constant, measured in meters per square second.

$d$ - Straight line distance between the center of mass and the pivot point of the pendulum, measured in meters.

$I_{O}$ - Moment of inertia with respect to pivot point, measured in $kg\cdot m^{2}$ .

In addition, frequency and angular frequency are both related by the following formula:

$\omega =2\pi\cdot f$

Where:

$f$ - Frequency, measured in hertz.

If $f = 0.658\,hz$ , then angular frequency of the physical pendulum is:

$\omega = 2\pi \cdot (0.658\,hz)$

$\omega = 4.134\,\frac{rad}{s}$

From the formula for the physical pendulum's angular frequency, the moment of inertia is therefore cleared:

$\omega^{2} = \frac{m\cdot g \cdot d}{I_{o}}$

$I_{o} = \frac{m\cdot g \cdot d}{\omega^{2}}$

Given that $m = 1.15\,kg$ , $g = 9.807\,\frac{m}{s^{2}}$ , $d = 0.425\,m$ and $\omega = 4.134\,\frac{rad}{s}$ , the moment of inertia associated with the physical pendulum is:

$I_{o} = \frac{(1.15\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.425\,m)}{\left(4.134\,\frac{rad}{s} \right)^{2}}$

$I_{o} = 0.280\,kg\cdot m^{2}$

The rotational inertia of the pendulum around its pivot point is $0.280\,kg\cdot m^{2}$ .

8 0

3 years ago

What is the formula for displacement

pogonyaev

Displacement is usually given to you as it is, but you can also get displacement through velocity by Δd= Δv*t, where Δv is the change in velocity and t is the change in time.

4 0

3 years ago

A projectile is shot directly away from Earth's surface. Neglect the rotation of the Earth.

Maksim231197 [3]

Answer:

Explanation:

We shall apply law of conservation of mechanical energy for projectile being thrown .

Total energy on the surface = total energy at height h required

a ) At height h , velocity = .351 x ( 2 GM/R x h )

$\frac{-GM}{R} + \frac{m\times(.351\times\sqrt{2GM})^2 }{2R } = \frac{-GMm}{R+h} + 0$