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Vlad [161]
3 years ago
5

What is the completely factored form of this polynomial? 18x^3 – 120x^2 – 42x

Mathematics
2 answers:
Nookie1986 [14]3 years ago
8 0
The completely factored form is 6x(3x+1)(x-7)
lyudmila [28]3 years ago
4 0

Answer:

6x(3x + 1)(x - 7) .

Step-by-step explanation:

First look for the greatest common factor of the 3 terms.

It is 6x, so

18x^3 – 120x^2 – 42x

= 6x(3x^2 - 20x - 7)

Now we look to factor the quadratic expression in the parentheses:

Use the 'ac' method:

The first and last coefficients are multiplied

3 * -7 = -21.

We look for 2 numbers whose product is -21 and whose sum is -20:

They are -21 and + 1 , so we write:

6x(3x^2 - 21x + 1x - 7)

= 6x [ (3x(x - 7) + 1(x - 7)]    Note that x - 7 is common, so:

= 6x(3x + 1)(x - 7)  Answer

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