3) If an object has a net negative charge of 4.0 Coulombs, the object possesses
1 answer:
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Answer:
1341.03 V/m
Explanation:
The power output per unit area is the intensity and also the is the magnitude of the Poynting vector.
= cε₀
⇒ = cε₀
Where;
P is the power output
A is the area of the beam
c is speed of light
ε₀ is permittivity of free space 8.85 × 10⁻¹² F/m
is the average (rms) value of electric field
Making electricfield the subject of the equation
= P / Acε₀
= √(P / Acε₀)
But area A = πr²
= √(P / πr²cε₀)
Given:
Output power, P = 15 mW = 0. 015 W
Diameter, d = 2 mm = 0.002 m
⇒ Radius,
Solving for average (rms) value of electric field;
= 1341.03 V/m
Answer:
<em>A = 0.05 V</em>
Explanation:
<u>Sinusoidal Functions</u>
A sinusoid or sinusoidal function is a sine or cosine which general equation is
Or also
Where A is the amplitude or maximum value, w is the angular frequency, t is the time and is the phase shift.
Comparing the given expression with the general formula
We can establish that A=50 mV = 0.05 V