Answer:
Explanation:
Psychological perspectives: Anxiety disorders: Identification and intervention. of situations, and not just one, as in many other anxiety disorders. episodes, or worsen symptoms, but no single stressor can explain the course of the disorder.
According to the cognitive perspective, one creates coping responses by transforming the anxiety into fear, and develops a plan to deal with it, which will create a sense of security. State and trait anxiety refers to the personality traits of an individual.
plz mark as brainliest
The gravitational acceleration on the surface of planet A is:
where G is the gravitational constant,
is the mass of planet A and
its radius.
Similarly, the gravitational acceleration on the surface of planet B is:
The ratio between the gravitational acceleration on planet A and B becomes:
The problem says that the two masses are equal:
while planet A has 3 times the radius of planet B:
. Substituting into the ratio, we get:
so, gravity on planet B is 9 times stronger than planet A.
The solution to the problem is as follows:
Normal force is m*g plus 240 N*sin30.
<span>30 kg*9.8 m/s^2 + 240 N*sin30 = 414 N
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
The energy stored in the capacitor decreases to one-half (½) of its initial value when the distance between the plates is then reduced to d/2.
<h3>The energy stored in a capacitor.</h3>
Mathematically, the energy stored in a capacitor can be calculated by using this formula:
U = ½CV² or U = q²/2C
<u>Where:</u>
- V is the potential difference.
Thus, we can logically deduce that the energy stored in the capacitor decreases to one-half (½) of its initial value when the distance between the parallel plate capacitors is reduced to d/2.
Read more on charge here: brainly.com/question/4313738
#SPJ1
Answer:
11.4 m
Explanation:
We are given that
Total distance traveled by cab,d=214 m
Maximum speed of cab=v=315 m/min=
1 min =60 s
Acceleration of cab=
We have to find the distance traveled by the cab while accelerating to full speed from rest.
Initial speed o f cab=u=0
Substitute the values in the formula
Hence, the cab travel 11.4 m from rest to full speed.