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mars1129 [50]
2 years ago
9

What happens to the water and oil mixture when air is introduced

Chemistry
1 answer:
Amanda [17]2 years ago
4 0

well, the oil will come up on the surface of the water and lay there but introducing air does not do much. hope that helps
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Scientists utilize models for a variety of different purposes, but each type of scientific model has limitations. What might be
Nezavi [6.7K]
They are based in current knowledge 

6 0
3 years ago
Complete the table to summarize the properties of the different subatomic particles. Type in your answers.
Aloiza [94]

<h2>Complete the table to summarize the properties of the different subatomic particles. </h2>

Explanation:

Atom

It is a smallest particle which cant exist independently.

According To Dalton, atom was indivisible but later on, it was proved that atom can be subdivided into sub atomic particles called electron, proton & neutron.

These subatomic particles have marked properties .

Proton

  • It was discovered by E.Goldstein .
  • It is positively charged particle
  • It is present in nucleus .
  • Its mass is equal to 1.6726219 × 10⁻²⁷ kilograms

Neutron

  • It was discovered by E.chadwick .
  • It is neutral
  • It is present inside the nucleus .
  • It's mass is equal to 1.674927471×10⁻²⁷ kg

Electron

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  • It has negative charge .
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  • It is present outside the nucleus in shells .
4 0
2 years ago
Read 2 more answers
At 2°C, the vapor pressure of pure water is 23.76 mmHg and that of a certain seawater sample is 23.09 mmHg. Assuming that seawat
wariber [46]

Answer:

0.808  M

Explanation:

Using Raoult's Law

\frac{P_s}{Pi}= x_i

where:

P_s = vapor pressure of sea water( solution) = 23.09 mmHg

P_i = vapor pressure of pure water (solute) = 23.76 mmHg

x_i = mole fraction of water

∴

\frac{23.09}{23.76}= x_i

x_i = 0.9718

x_i+x_2=1

x_2 = 1- x_i

x_2 = 1- 0.9718

x_2 = 0.0282

x_i = \frac{n_i}{n_i+n_2}  ------ equation (1)

x_2 = \frac{n_2}{n_i+n_2}  ------ equation (2)

where; (n_2) = number of moles of sea water

(n_i) = number of moles of pure water

equating above equation 1 and 2; we have :

\frac{n_2}{n_i}= \frac{0.0282}{0.9178}

= 0.02901

NOW, Molarity =  \frac{moles of sea water}{mass of pure water }*1000

= \frac{0.02901}{18}*1000

= 0.001616*1000

= 1.616 M

As we assume that the sea water contains only NaCl, if NaCl dissociates to Na⁺ and Cl⁻; we have \frac{1.616}{2} =0.808 M

3 0
2 years ago
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The percent by mass of copper in CuBr2 is Use mc004-1.jpg. 28.45%. 44.30%. 63.55%. 71.55%.
Greeley [361]
First, we must find the total mass of CuBr₂:
Mass = 64 + 2 x 80
Mass = 224

Percentage mass of copper = mass of copper x 100 / total mass
Percentage mass of copper = (64 / 224) x 100
Percentage mass of copper = 28.45%
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2 years ago
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The natural process where the sun's energy is trapped by the atmosphere to make the Earth warm enough for life is known as
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The greenhouse effect captures the sun's energy and keeps the earth warm.
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