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3 years ago

What happens to the water and oil mixture when air is introduced

1 answer:

4 0

well, the oil will come up on the surface of the water and lay there but introducing air does not do much. hope that helps

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How does the comic strip define a polar molecule

zmey [24]

The answer is: A molecule with a difference in electrical charge between two ends.

Electronegativity (χ) is a property that describes the tendency of an atom to attract a shared pair of electrons.

Atoms with higher electronegativity attracts more electrons towards it, electrons are closer to that atom.

For example fluorine has electronegativity approximately χ = 4 and oxygen χ = 3,5, fluorine attracts electron and he has negative charge and oxygen has positive charge.

4 0

3 years ago

What is the temperature of 1.485 moles of N₂ gas at a pressure of 1.072 atm and a volume of 20 L?

morpeh [17]

Answer:

178.67K

Explanation:

PV=nRT

T=PV/nR

= 1.072atm*20L/1.485mol*0.0821LatmK^-1

=178.67K

8 0

3 years ago

For the following reaction, 4.07 grams of aluminum oxide are mixed with excess sulfuric acid. The reaction yields 10.4 grams of

torisob [31]

Answer:

Theoretical yield = 13.7 g

% yield =76 %

Explanation:

For $Al_2O_3$

Mass of $Al_2O_3$ = 4.07 g

Molar mass of $Al_2O_3$ = 101.96 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{4.07\ g}{101.96\ g/mol}$

$Moles\ of\ Al_2O_3= 0.0399\ mol$

According to the reaction:

$Al_2O_3+3H_2SO_4\rightarrow Al_2(SO_4)_3+3H_2O$

1 mole of $Al_2O_3$ on reaction produces 1 mole of $Al_2(SO_4)_3$

So,

0.0399 mole of $Al_2O_3$ on reaction produces 0.0399 mole of $Al_2(SO_4)_3$

Moles of $Al_2(SO_4)_3$ obtained = 0.0399 mole

Molar mass of $Al_2(SO_4)_3$ = 342.2 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$0.0399= \frac{Mass}{342.2\ g/mol}$

$Mass= 13.7\ g$

<u>Theoretical yield = 13.7 g</u>

The expression for the calculation of the percentage yield for a chemical reaction is shown below as:-

$\%\ yield =\frac {Experimental\ yield}{Theoretical\ yield}\times 100$

Given , Values from the question:-

Theoretical yield = 13.7 g

Experimental yield = 10.4 g

Applying the values in the above expression as:-

$\%\ yield =\frac{10.4}{13.7}\times 100$

<u>% yield =76 %</u>

6 0

3 years ago

Used all my points please help with Lesson 13: Matter and Energy Unit Test

fredd [130]

Answer:

oceans rise and temputer in creses.

Explanation:

3 0

3 years ago

What are some differences between an “ideal” gas and real gases?

gogolik [260]

Answer:

The Ideal Gases are described under the standard conditions to eliminate as many variables as possible.

Explanation:

P*V = n*R*(temp final-temp initial) There are standard conditions for the relationships between pressure (P), Volume (V), number of moles (n), and the temperature in Kelvin (K) or Celsius (C).

7 0

3 years ago