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valentina_108 [34]
3 years ago
7

How many liters of CO2 gas can be produced at 30.0 °C and 1.50 atm from the reaction of 5.00 mol of C3H8 and an excess of O2 acc

ording to the following equation? C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g)
Chemistry
1 answer:
lbvjy [14]3 years ago
5 0

Answer:

249 L

Explanation:

Step 1: Write the balanced equation

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(g)

Step 2: Calculate the moles of CO₂ produced from 5.00 moles of C₃H₈

The molar ratio of C₃H₈ to CO₂ is 1:3. The moles of CO₂ produced are 3/1 × 5.00 mol = 15.0 mol

Step 3: Convert "30.0°C" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 30.0°C + 273.15 = 303.2 K

Step 4: Calculate the volume of carbon dioxide

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T/P

V = 15.0 mol × 0.0821 atm.L/mol.K × 303.2 K/1.50 atm

V = 249 L

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Answer:

Total mass of leaked fluorine in six months= 0.405 kg

Explanation:

From the given,

Leaked mass of freon = 35.12 gm

Molecular mass of freon = C_{2}H_{2}F_{3}Cl = (2\times 12)+(2\times1)+(3\times19)+(1\times35.5)=118.5g/mol

Total weeks per month = 4

Fluorine released into the air in total weeks = 6/times4=24

3 molecules of fluorine is present in the freonC_{2}H_{2}F_{3}Cl

{\tex Mass\,leak\,rate\,of\,fluorine}\,= \frac{Mass\,of\,fluorine\,in\,freon}{Molecularmass\,of\,freon}\times leak\,rate

\frac{19\times 3}{118.5}\times 35.12=16.8gm/week

Total mass of fluorine leaked in six months = 24\times16.9=405.6gm= 0.405 kg

6 0
3 years ago
The halogens like to bond with what other group?
labwork [276]
Halogens are most likely to bond with Alkaline Earth Metals and Alkali metals.
6 0
3 years ago
4. Why does the metallic character of the alkaline earth metals increase as you go down the
tino4ka555 [31]

As you proceed down the periodic table, the metallic character becomes stronger. This is because as the atomic radius increases, there is less attraction between the nucleus and the valence electrons due to the greater distance between them, making electrons simpler to shed.

4 0
2 years ago
A student wishes to prepare 25mL of 0.1M NaOH from 6M NaOH.
liraira [26]

Answer:

Na(OH)4

Explanation:

Look at the charges and add them up

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7 0
2 years ago
if 334.6 g of phosphoric acid is reacted with excess potassium hydroxide. the final mass K3PO4 produced is found to be 248g. wha
Orlov [11]

Answer:

                     %age Yield  =  34.21 %

Explanation:

                   The balance chemical equation for the decomposition of KClO₃ is as follow;

                            3 KOH + H₃PO₄ → K₃PO₄ + 3 H₂O

Step 1: Calculate moles of H₃PO₄ as;

Moles = Mass / M/Mass

Moles = 334.6 g / 97.99 g/mol

Moles = 3.414 moles

Step 2: Find moles of K₃PO₄ as;

According to equation,

                 1 moles of H₃PO₄ produces  =  1 moles of K₃PO₄

So,

              3.414 moles of H₃PO₄ will produce  =  X moles of K₃PO₄

Solving for X,

                      X = 1 mol × 3.414 mol / 1 mol

                      X = 3.414 mol of K₃PO₄

Step 3: Calculate Theoretical yield of K₃PO₄ as,

Mass = Moles × M.Mass

Mass = 3.414 mol × 212.26 g/mol

Mass = 724.79 g of K₃PO₄

Also,

%age Yield  =  Actual Yield / Theoretical Yield × 100

%age Yield  =  248 g / 724.79 × 100

%age Yield  =  34.21 %

3 0
3 years ago
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