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Romashka [77]
3 years ago
6

When you push on a wall can you push harder on the wall than it can on you?

Physics
1 answer:
IgorLugansk [536]3 years ago
5 0

Every action have an equal and opposite reaction.

When you push with a force it will push on you with the same force

You might be interested in
Two students stand poised to leap off a high dive structure into the swimming pool below. Student B is twice as massive as stude
iogann1982 [59]

Answer: option (D)

Explanation:

The potential energy of each of the students is given below as

P.E(student A) = mgh, where m = mass of student A, g is acceleration due to gravity and h = height of the high dive structure.

The mass of student B is twice as much as that of A, hence his mass is 2m and his potential energy is given below as

P.E ( student B) =2mgh = 2(mgh)

Recall that the relationship between potential energy and work done is that

Work done = - (change in potential)

For student A, work done = - mgh

For student B, work done = - 2mgh

From the equations above it can be seen that student B will do twice the work in getting to the high dive structure than student A hence validating option D.

8 0
3 years ago
How does a scientific theory compare to a scientific law?
shusha [124]

Answer:

In general, a scientific law is the description of an observed phenomenon. It doesn't explain why the phenomenon exists or what causes it. The explanation of a phenomenon is called a scientific theory. It is a misconception that theories turn into laws with enough research.

Explanation:

Hope this helped

6 0
3 years ago
Read 2 more answers
A gas bottle contains 7.86×10^23 Oxygen molecules at a temperature of 327.0 K.
castortr0y [4]

Answer:

1.  E=5320.3J

2. E= 1773.45J

3. E=6.76*10^{-21}J

4. E=2.25*10^{-21}J

Explanation:

1. the thermal energy is given by the formula

E_T=\frac{3}{2}NK_BT=\frac{3}{2}(7.86*10^{23})(1.38*10^{-23}\frac{J}{K})(327.0K)=5320.3J

where KB is the Boltzmann's constant, T is the temperature and N is the number of molecules in the system.

2. Each degree of freedom contains one half of the total energy. Hence, the energy for one degree of freedom is

E_1=\frac{1}{2}NK_BT=1773.45J

3.

E=\frac{3}{2}K_BT=6.76*10^{-21}J

4.

E=\frac{1}{2}K_BT=2.25*10^{-21}J

Hope this helps!!

6 0
3 years ago
A hockey puck sliding at 60.0m/s slows uniformly to 20.0m/s while travelling 800.0m.
julia-pushkina [17]
A) -3.75 meters/second
A=(20^2-80^2)/(2x800)
=(400-6400)/1600
=-6000/1600
=-3.75
B) 16 seconds
t=(20-80)/-3.75
=-60/-3.75
=16
3 0
3 years ago
The energy transferred to the water in 100 seconds was 155 000 J. specific heat capacity of water = 4200 J/kg °C
skelet666 [1.2K]

Answer:

0.37 kg

Explanation:

I'm not a professor myself, but this is how I worked it out:

using the graph, after 100 seconds, the temperature is 100 degrees Celsius.

If we now substitute everything into the specific heat capacity equation, making the mass "m", we would come up with:

4200 = 155000/(m x 100)

If we rearrange and solve for m, we get 0.37 kg.

I'm not sure if I have done this correctly, feel free to correct me.

Hope this helps!

4 0
3 years ago
Read 2 more answers
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