2.0 g 1.0g 0.5g 0.25g
3 and a half lives = 42 days
Answer:
The answer to your question is: 0.3 moles of AgNO₃
Explanation:
1.0 L sample
0.1 mol of NaCl
0.1 mol of CaCl₂
AgNO₃ = ? moles
Reactions
NaCl + AgNO₃ ⇒ AgCl + NaNO₃
Then 1 NaCl mol --------------- 1 AgNO₃
0.1 mol -------------- x
x = 0.1 moles of AgNO₃ needed
CaCl₂ + 2 AgNO₃ ⇒ 2 AgCl + Ca(NO₃)₂
Then 1 mol of CaCl₂ ------------- 2 moles of AgNO₃
0.1 mol ------------- x
x = 0.2 moles of AgNO₃
Total moles of AgNO₃ = 0.1 + 0.2 = 0.3