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andrey2020 [161]
3 years ago
11

The correct name for a “shooting star” is a:

Engineering
2 answers:
nirvana33 [79]3 years ago
8 0

Answer:

There is no "correct" name, but the scientific name could be meteorite.

goldfiish [28.3K]3 years ago
3 0

Answer:

meteor

Shooting star may refer to a meteor.

Explanation:

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In Lab 7, we worked through a program that displayed the homeless shelter occupancy over time. The same approach can be used for
Bezzdna [24]

Answer:

Explanation:

The python code to generate this is quite simple to run.

i hope you understand everything written here, you can as well try out other problems to understand better.

First to begin, we import the package;

Code:

import pandas as pd

import matplotlib.pyplot as plt

name = input('Enter name of the file: ')

op = input('Enter name of output file: ')

df = pd.read_csv(name)

df['Date'] = pd.to_datetime(df["Date"].apply(str))

plt.plot(df['Date'],df['Absent']/(df['Present']+df['Absent']+df['Released']),label="% Absent")

plt.legend(loc="upper right")

plt.xticks(rotation=20)

plt.savefig(op)

plt.show()

This should generate the data(plot) as seen in the uploaded screenshot.

thanks i hope this helps!!!

6 0
3 years ago
96/64 reduced to its lowest term
Marina CMI [18]

Answer:

3/2

Explanation:

8 0
3 years ago
Does anybody know what plane this is? i saw it the other day doing a low pass through my community
Arlecino [84]

Answer:

Airbus A340-313

Explanation:

it is what it is

3 0
2 years ago
Application 1: Consider the following beam under combined loading of a distributed pressure and applied bending moment. Complete
Ivan

Answer:

Explanation:

kindly check he attached file below

7 0
3 years ago
The mean of hours that the average person watches television each day is 4.18 hours with a standard deviation of 1.19 hours. Fin
luda_lava [24]

Answer:

z = \frac{3-4.18}{1.19}=-0.992

z = \frac{5-4.18}{1.19}=0.689

And we can find this probability with this difference:

P(-0.992

And then we can conclude that the probability that someone watches between 3 and 5 hours a day is approximately 0.591 using a normal distribution

Explanation:

For this case we can define the random variable X as "hours that a person watches television". For this case we don't have the distribution for X but we have the following parameters:

\mu = 4.18,\sigma =1.19

We can assume that the distribution for X is normal

X \sim N(\mu = 4.18 , \sigma =1.19)

And we want to find this probability:

P(3

And we can use the z score formula given by:

z=\frac[X- \mu}{\sigma}

And we can find the z score for each limit and we got:

z = \frac{3-4.18}{1.19}=-0.992

z = \frac{5-4.18}{1.19}=0.689

And we can find this probability with this difference:

P(-0.992

And then we can conclude that the probability that someone watches between 3 and 5 hours a day is approximately 0.591 using a normal distribution

6 0
3 years ago
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