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sergiy2304 [10]
3 years ago
8

If the motor M rotates in the direction shown by the arrow as illustrated in the diagram below, what is going on? A. 1 and 2 are

going down B. 1 goes up and 2 goes down C. 1 and 2 are going up D. 1 goes down and 2 goes up 49) For the system in the diagram below to be in equilibrium, what is the mass of P in pounds? The mass at the other end of the beam is 5 kg.
Physics
1 answer:
madreJ [45]3 years ago
7 0

Answer:

C. 1 and 2 are going up

Explanation:

The motor turns counterclockwise, so the pulley above it will also turn counterclockwise.  This means the pulley to the right will turn counterclockwise.  So block 2 will move up.

Since the belt is twisted on the left side, the pulley on the left will spin in the opposite direction (clockwise).  So block 1 will also move up.

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11Alexandr11 [23.1K]
Given a = 10 cm/s²
          u = 0 cm/s
          v = 50 cm/s
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3 years ago
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3 years ago
Can someone help me with this please?
Slav-nsk [51]

Answer:

C2, C1, C4, C5 and C6 are in parallel. Therefore, we use the formula Cp = C1 + C2 + ....

Cp = C2 + C1 + C4 + C5 + C6 = ( 7 * 10 ^-3) + (18 * 10^-6) + (0.8F) + (200 * 10^-3 F) + (750 * 10^-6) = 1.008F

Now, Cp will become one capacitor and it will be aligned with C3, therefore it will now become a circuit in series.

We use the formula: 1/Cs = 1/C1 + 1/C2 + .... + ....1/Cn

Thus,

1/Cs = 1/C3 + 1/Cp

1/Cs = 1/(14 * 10^-3 F) + 1/(1.008F)

Cs = 1.4 * 10 ^-2 or if we do not round too much it will give exactly 0.0138 F

So the answer should be a)

8 0
3 years ago
How far will a 600 kg boat travel in 10 s if there is a constant 900 N force on it and it starts from rest?
natta225 [31]

Answer:

here

Explanation:

There are two forces acting upon the skydiver - gravity (down) and air resistance (up). The force of gravity has a magnitude of m•g = (72 kg) •(9.8 m/s/s) = 706 N. ... a 3.25-kg object rightward with a constant acceleration of 1.20 m/s/s if the force of ... of 33.8 kg, how far (in meters) will it move in 1.31 seconds, starting from rest?

4 0
2 years ago
Someone help please by providing work and answers please :)
cupoosta [38]
There are two ways to solve this. The longer way is to use those equations to calculate numbers for total distance.

The easier way is to find the area under the graph. That's right, AREA UNDER VELOCITY-TIME graph is the TOTAL DISTANCE travelled!

it's a shortcut.

Let's split up the area into a triangle and rectangle:

Triangle = 0.5(4-0)(10-0) = 20 m
Rectangle = (6-4)(10-0) = 20 m

Total distance = 40 m!
6 0
3 years ago
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