Pretty sure it’s ,B. Microscope!
Answer;
=28.09 amu
Explanation;
In this problem, they did not give us the percentages. However, since we know the number of atoms, we can easily calculate the percentages. For example:
(460 X 100)/500 = 92%
If we do this for all three isotopes,
(460 × 25)/500 = 5 %
(460 × 15) /500 = 3%
-We get 92%, 5%, and 3%. (We'll assume these are absolute numbers for determining our significant figures).
Now the problem is just like the previous one. First convert the percentages into decimals. Then multiply those decimals by the masses and add. Here's the solution:
= (0.92) X (27.98 amu) + (0.05) X (28.98 amu) + (0.03) X (29.97 amu)
= 25.74 amu + 1.449 amu + 0.8991 amu
= 28.09 amu
Answer:
See below in bold.
Explanation:
Nitrogen, Hydrogen and Oxygen are the elements present in ammonium nitrate.
The Molar Mass = 2N + 4H + 3 O
= 2*14.007 + 4*1.008 + 3*15.999
= 80.043.
Percentage of Nitrogen = (2 * 14.007) * 100 / 80.043
= 35.00 %.
Percentage of Hydrogen = (4* 1.008) * 100 / 80.043
= 5.04%.
Percentage of Oxygen = (3 * 15.999) * 100 / 80.043
= 59.96 %.
The elements toward the bottom left corner of the periodic table are the metals that are the most active in the sense of being the most reactive. Lithium, sodium, and potassium all react with water, for example.
