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harina [27]
3 years ago
14

You walk 4.5 km in one direction then make a 45 degree turn to the right and walk another 6.4 km what is the magnitude of your d

isplacement
Physics
1 answer:
uranmaximum [27]3 years ago
6 0

Answer:

The magnitude of your displacement is 4.52 Km

Explanation:

Initially you walk 4.5 km in one direction. Then after turning to 45 degrees then you walk 6.4 km

So let us use cosine formula to find the distance

Distance = \sqrt{a^2 +b^2 -2abcos(angle)

Substituting the given values

Distance = \sqrt{4.5^2 +6.4^2 -2(4.5)(6.4)cos(45)}

Distance = \sqrt{20.25+40.96 -2(4.5)(6.4)(0.707)}

Distance = \sqrt{20.25+40.96 -2(28.8)(0.707)}

Distance = \sqrt{20.25+40.96 - (57.6)(0.707)}

Distance = \sqrt{20.25+40.96 - 40.72}

Distance = 4.52 km

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A 1060-kg car moving west at 16 m/s collides with and locks onto a 1830-kg stationary car. determine the velocity of the cars ju
iren [92.7K]
M1U1 + M2V2 = (M1+M2)V, where M1 is the mass of the moving car, M2 is the mass of the stationary car, U1 is the initial velocity, and V is the common velocity after collision.
therefore; 
(1060× 16) + (1830 ×0) = (1060 +1830) V
 16960 = 2890 V
      V = 5.869 m/s
The velocity of the cars after collision will be 5.689 m/s
5 0
3 years ago
During an auto accident, the vehicle's air bags deploy and slow down the passengers more gently than if they had hit the windshi
vladimir2022 [97]

Answer:

At a deceleration of 60g, or 60 times the acceleration due to gravity a person will travel a distance of 0.38 m before coing to a complete stop

Explanation:

The maximum acceleration of the airbag = 60 g, and the duration of the acceleration = 36 ms or 36/1000 s or 0.036 s

To find out how far (in meters) does a person travel in coming to a complete stop in 36 ms at a constant acceleration of 60g

we write out the equation of motion thus.

S = ut + 0.5at²

wgere

S = distance to come to complete stop

u = final velocoty = 0 m/s

a = acceleration = 60g = 60 × 9.81

t = time = 36 ms

as can be seen, the above equation calls up the given variable as a function of the required variable thus

S = 0×0.036 + 0.5×60×9.81×0.036² = 0.38 m

At 60g, a person will travel a distance of 0.38 m before coing to a complete stop

7 0
3 years ago
Russell bradley carried 207 kg of bricks 3.65 m up a ladder. If the amount of work required to perform that task is used to comp
MrRa [10]

Answer:

Explanation:

Work done in carrying bricks

mgh

= 207 x 9.8 x 3.65

-= 7404.4 J

Work done in compressing gas

PΔV

Pressure x change in volume

1.8 x 10⁶ ΔV = 7404.4

ΔV  = 7404.4  / 1.8 x 10⁶m³

= 4113.33 x 10⁻⁶ m³

= 4113.33 cc

8 0
3 years ago
Read 2 more answers
A body weighs 100newtons when submerged in water. calculate the upthrust action on the body​
Andrews [41]

Answer:

Upthrust = 20 N

Explanation:

The question says that "A body weighs 100N in air and 80N when submerged in water. Calculate the upthrust acting on the body ?"

Upthrust is defined as the force when a body is submerged in liquid, then liquid applies a force on it.

ATQ,

Weight of body in air is 100 N

Weight of body in water is 80 N

Upthrust is equal to the weight of body in air minus weight of body in water.

Upthrust = 100 N - 80 N

Upthrust = 20 N

So, 20 N of upthrust is acting on the body.

7 0
3 years ago
Can someone tell me the answer and the reason
spin [16.1K]

Answer:

(a) the blocks all had different masses.

Explanation:

The surface is smooth, therefore coefficient of friction is tending to zero.

Forces for each blocks varied from 6N to 8N to 7N to 5N

The blocks were made of different materials and different materials are going to have varying weight for the same size of block.

8 0
3 years ago
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