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Mnenie [13.5K]
3 years ago
8

A ticker-tape is moved through a ticker-timer for 5 seconds . if the timer is operating at 25 Hz. i.How many dots would have bee

n printed on the tape? ii.What kind of motion does the tape represent ? give reason​
Physics
1 answer:
svetlana [45]3 years ago
8 0

Answer:

Explanation:

25 cycles/s (5 s) = 125 dots

Tape does Repetitious motion.

It might possibly be harmonic motion, but we do not have enough information to say for certain.

You might be interested in
3)(20pts) Un barco invasor se encuentra a 560m de un puerto de defensa, el puerto tiene cañones que
Eduardwww [97]

a) Las balas de cañon disparadas desde el puerto deben tener una ángulo de 27.39° para que puedan impactar al barco, con una velocidad inicial de 82 m/s.

b) El tiempo de vuelo de las balas de cañon para alcanzar al barco que está a 560 m de distancia es de 7.69 s.

c) Sabiendo que el ángulo calculado en el inciso a) es para una distancia de 560 m, el barco debe estar a una distancia mayor para que las balas no lo alcancen.

a)

Podemos usar las ecuaciones de tiro parabólico para encontrar el ángulo que permita derribar al barco invasor.

x=\frac{v_{i}^{2}sin(2\alpha)}{g} (1)

Donde:

  • v(i) es la velocidad inicial del cañon (82 m/s)
  • α es el ángulo de tiro
  • g es la gravedad (9.81 m/s²)
  • x es el desplazamiento total (560 m)

Lo que debemos hacer es depejar α de la ecuación 1

sin(2\alpha)=\frac{xg}{v_{i}^{2}}

sin(2\alpha)=\frac{560*9.81}{82^{2}}

sin(2\alpha)=0.82

\alpha=\frac{sin^{-1}(0.82)}{2}

\alpha=27.39^{\circ}

Por lo tanto, el ángulo para que el cañón impacte en el barco es de 27.39 °.

b)

Sabemos que la componente de la velocidad en el eje x es constante, así que podemo usar la siguiente ecuación.

v_{x}=\frac{x}{t}

La componente x de la velocidad es V(x) = V(i)cos(α) y sabiendo la distancia total de 560 m, el tiempo será:

v_{i}cos(\alpha)=\frac{x}{t}

t=\frac{x}{v_{i}cos(\alpha)}

t=\frac{560}{82cos(27.39)}

t=7.69\: s

El tiempo total de vuelo de las balas de cañon es de 7.69 s.

c)

Sabemos que el ángulo calculado en el inciso a) es de 27.39 °, y ese valor fue calcualdo para una distancia de 560 m, por lo tanto el barco debe estar a una distancia mayor que esa para que las balas no lo alcancen.

Puedes encontrar más información sobre tiro parabólico aquí:

https://brainly.lat/tarea/3605927

Espero te haya sido de ayuda!

3 0
3 years ago
How does the resistance of the following change with rhe rise in temperature ? pure metals and German silver and carbon​
Archy [21]

resistance in the increasing order from least to maximum:

German silver, pure metals, carbon

4 0
3 years ago
Read 2 more answers
A 20.00-ohm, 5.00-watt resistor is placed in series with a power supply.(a) What is the maximum voltage that can be applied to t
Nutka1998 [239]
<h2>Answer:</h2>

(a) 10.00V

(b) 0.5V

<h2>Explanation:</h2>

(a) The power(P) supplied by a resistor of resistance (R) when a voltage(V) is passed across is given by;

P = V² / R       ------------------(i)

From the question;

P = 5.00W

R = 20.00Ω

Substitute these values into equation (i) as follows;

5.00 = V² / 20.00

V² = 5.00 x 20.00

V² = 100.00

V = \sqrt{100.00}

Solve for V;

V = 10.00V

Therefore, the maximum voltage that can be applied without harming the resistor is 10.00V

(b) By Ohm's law the current (I) flowing through a resistor of resistance (R) when a voltage (V) is applied is given by;

V = I x R

=> I = V / R             ----------------(ii)

Substitute the values of V and R into equation (ii) as follows;

I = 10.00 / 20.00

I = 0.5A

Therefore, the current through the resistor is 0.5A

7 0
3 years ago
A certain car is capable of accelerating at a uniform rate of 0.85 m/s^2. What is the magnitude of the car's displacement as it
gogolik [260]

Solution: 85.11 m

Given:

acceleration of the car, a= 0.85 m/s^{2}

initial velocity,u=83km/h=23.05 m/s

final velocity, v=94 km/h=26.11 m/s

we need to find the displacement (s) of the car.

we would use the equation of motion:

2as=v^{2}-u^{2}\\&#10;\Rightarrow s=\frac{v^{2}-u^{2}}{2a} \\&#10;\Rightarrow s=\frac{26.11^{2}-23.05^{2}}{2\times0.85}\\&#10;\Rightarrow s=85.11 m

hence, the displacement done by the car is = 85.11 m

7 0
3 years ago
A pair of bullocks exerts a force of 140 N on a plough. The field being ploughed is 15 m long. How much work is done in ploughin
Dahasolnce [82]

Answer:

2100 J

Explanation:

Work = force × distance

W = Fd

W = (140 N) (15 m)

W = 2100 J

3 0
4 years ago
Read 2 more answers
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